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Maksim231197 [3]
2 years ago
15

Over the first five years of owning her car, Gina drove about 12,200 miles the first year, 16,211 miles the second year, 12,050

the third year, 11,350 the fourth year, and 13,325 the fifth year. Find the mean, median, and mode of this data.
mean = 12,200; median = 12,200; no mode
mean = 13,027; median = 12,200; mode = 4,861
mean = 12,200; median = 13,027; no mode
mean = 13,027; median = 12,200; no mode
Mathematics
2 answers:
vampirchik [111]2 years ago
8 0
(12,200 + 16,211 + 12,050 + 11,350 + 13,325) / 5 = 65136/5 = 
13027.2 <== this is the mean (average)

11,350 , 12,050 , 12,200 , 13,325, 16,211
median (middle number) = 12,200

there is no mode...a mode is a number that appears most often...all the numbers appear once in this data.

attashe74 [19]2 years ago
7 0
The answer is <span>mean = 13,027; median = 12,200; no mode
</span>
Let's rearrange values from the lowest to the highest:
11350, 12050, 12200, 13325, 16211

<span>The mean is the sum of all values divided by the number of values:
</span>(11350 + 12050 + 12200 + 13325 + 16211)/5 ≈ 13027

The median is the middle value. If there is an odd number of data, then the median is the value in the middle. In the data set 11350, 12050, 12200, 13325, 16211, the median (the middle value) is 12200

<span>The mode is the value that occurs most frequently. Since none of the number does not occur most frequently, there is no mode.
</span>
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2 years ago
HELP PLEASE AND THANK YOU 1JAAB
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\bold{Q1}\ side\ BD\\\\\bold{Q2}\ \angle5\ \leftrightarrow\ \angle6\\\\\bold{Q3}\ \triangle TAP\\\\\bold{Q4}\ \triangle APT

Step-by-step explanation:

For Q1 and Q2

\text{If}\ AB\cong AC,\ BD\cong CD,\ RSTU\ \text{is a parallelogram (rectangle)},\ \text{then}\\\\\angle 1\ \leftrightarrow\ \angle2\\\angle3\ \leftrightarrow\ \angle4\\\angle C\leftrightarrow\ \angle B\\\angle 5\ \leftrightarrow\ \angle6\\\angle7\ \leftrightarrow\ \angle 8\\\angle R\ \leftrightarrow\ \angle T\\\angle S\ \leftrightarrow\ \angle U

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4 0
3 years ago
A 10-year annuity pays $1,850 per month, and payments are made at the end of each month. If the APR is 12 percent compounded mon
Fittoniya [83]

Based on the amount the annuity pays per month and the APR, the value of the annuity today is $133,349.85.

<h3>What is the present value of the annuity?</h3>

First, find the present value of the annuity at 5 years:

= 1,850 x present value interest factor of annuity, 60 months, 8/12%

= 1,850 x 49.32

= $91,242

Then find the present value of the annuity from 5 years till date:

= (1,850 x present value interest factor of annuity, 60 months, 12/12%) + ( 91,242) / (1 + 1%)⁶⁰)

= (1,850 x 44.955) +  ( 91,242) / (1 + 1%)⁶⁰)

= $133,349.85

Find out more on the present value of annuities at brainly.com/question/24097261.

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4 0
1 year ago
Suppose you want to create a set of weights so that any object with an integer weight from 1 to 40 pounds can be balanced on a t
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Answer:

You need 4 weights, and the weights are 1; 3; 9 and 27.

Step-by-step explanation:

<em>Since the scale has two plates, we can place weights on either side and also the object so it can be balanced. </em>

This is a key part of the problem, it's not only on the other side of the scale, but on both sides.

Let's do the math now.

If i get two weights, 1 and 3. I can form this combinations.

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With a weight of 9, now i can add all the integers up to 13lb.

And the next step? Lets add one more. Keeping the last rule, the weight would have to have a difference with the last object plus one. So if i grab 27, 27 minus 13 is 14. And that is a difference witht the last object plus 1.

The sum of all the weights adds up to 40 pounds. And i can balance any integer in the middle.

The formula we are using is p – n = n + 1

Where p is the new weight. and n is the last object we weighted. And the sum of the weights goes up to the last object we can place on the scale, and in this case is 40.

4 0
3 years ago
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