(8x2.3)= (18.4)
(2.1x4)= (8.4)
Now you should have:
41-9+18.4-15+8.4
9+18= 27
15+8.4= 23.4
Should have:
41-27-23.4= -9.4
$140(.075) = 10.5
10.5+140= 150.50
the total would be $150.50
Answer:
slope of M'N' = 1
Explanation:
First, we will need to get the coordinates of points M' and N':
We are given that the dilation factor (k) is 0.8
Therefore:
For point M':
x coordinate of M' = k * x coordinate of M
x coordinate of M' = 0.8 * 2 = 1.6
y coordinate of M' = k * y coordinate of M
y coordinate of M' = 0.8 * 4 = 3.2
Therefore, coordinates of M' are (1.6 , 3.2)
For point N':
x coordinate of N' = k * x coordinate of N
x coordinate of N' = 0.8 * 3 = 2.4
y coordinate of N' = k * y coordinate of N
y coordinate of N' = 0.8 * 5 = 4
Therefore, coordinates of M' are (2.4 , 4)
Then, we can get the slope of M'N':
slope = (y2-y1) / (x2-x1)
For M'N':
slope = (3.2-4) / (1.6-2.4)
slope = 1
Hope this helps :)
Answer:
Step-by-step explanation:
Given that a small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company for over 10 years. So remaining 75 are between 5 and 10 years.
Suppose that one employee is selected at random from a list of the employees
A) Probability that the selected employee has been with the firm less than 5 years = ![\frac{50}{250 } \\= 0.20](https://tex.z-dn.net/?f=%5Cfrac%7B50%7D%7B250%20%7D%20%5C%5C%3D%200.20)
B) Probability that the selected employee has been with the firm between 5 and 10 years
= ![\frac{75}{250 } \\= 0.30](https://tex.z-dn.net/?f=%5Cfrac%7B75%7D%7B250%20%7D%20%5C%5C%3D%200.30)
C) Probability that the selected employee has been with the firm more than 10 years
= ![\frac{125}{250} =0.50](https://tex.z-dn.net/?f=%5Cfrac%7B125%7D%7B250%7D%20%3D0.50)
a) P(A) = 0.2
P(C) = 0.5
P(A or B) = 0.2+0.3 = 0.5
P(A and C) = 0 (since A and C are disjoint)
1 and 3/4 is the answer!
Hope this helps! May I have brainliest? :D