Quadrilateral BCDE is inscribed in circle A as shown. `bar(BD)` divides the quadrilateral into two triangles, `DeltaBCD` and `De
ltaBED`. Which statement is true about the triangles?
A. The angle bisectors and the perpendicular bisectors for both triangles intersect at the same point.
B. The angle bisectors of `DeltaBCD` intersect at the same point as those of `DeltaBED`.
C. The perpendicular bisectors of `DeltaBCD` intersect at the same point as those of `DeltaBED`.
D. The angle bisectors of `DeltaBCD` intersect at the same point as the perpendicular bisectors of `DeltaBED`.
A. The angle bisectors and the perpendicular bisectors for both triangles intersect at the same point.
B. The angle bisectors of `DeltaBCD` intersect at the same point as those of `DeltaBED`.
C. The perpendicular bisectors of `DeltaBCD` intersect at the same point as those of `DeltaBED`.
D. The angle bisectors of `DeltaBCD` intersect at the same point as the perpendicular bisectors of `DeltaBED`.
2 answers:
Answer with explanation:
→It is given that, Quadrilateral BCDE is inscribed in circle , and segment BD divides the Quadrilateral into two triangles , ΔBED and Δ B CD.
⇒To determine the center of circle,draw perpendicular bisector of any two chords.BC,CD,DE,BD and EB are chords of the circle.
→The Point where , the the perpendicular bisector of sides of Quadrilateral meet is center of the circle.
→ So, the perpendicular bisector of sides of ΔBED, that is ,BE,B D, and ED meet at the center of the circle.
→Similarly, the perpendicular bisector of sides of ΔB CD, that is ,BC,C D, and B D meet at the center of the circle.
Option C: The perpendicular bisectors of `ΔBCD` intersect at the same point as those of ΔBED.`
You might be interested in
Answer is
When it's powered numbers, remember to choose the one with the largest power. For example,
And
Choose 10, same goes to y, where you choose 7 not 4 since 7 is larger.
Hope this helps. - M