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rosijanka [135]
3 years ago
8

A rowing team rowed 120 kilometers while going with the current in the same amount of time as it took to row 20 kilometers going

against the current. The rate of the current was 10 kilometers per hour. Find the rate of the rowing team in still water.
Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

100/x+6=20/x-6

100x-600=20x+120

80x=720

x=9 miles an hour as the rowing teams' rate in still water

Sauron [17]3 years ago
5 0
Your answer is=100/x600=20x+120
Hopefully this will help you!
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192 is what percent of 600
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The distance of a door knob from the floor is about one......
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The distance of a door knob from the floor is about one hip I guess
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When a cold drink is taken from a refrigerator, its temperature is 5°C. After 25 minutes in a 20°C room its temperature has incr
Andrews [41]

Answer:

  (a)  13.85 °C

Step-by-step explanation:

The temperature difference is a decaying exponential function of time. Here, it decreases from an initial difference of 15 °C to 10 °C after 25 minutes. So, that temperature difference can be modeled as ...

  ΔT = 15(10/15)^(t/25)

We want to find the value of this at t=55. It is ...

  ΔT = 15(2/3)^(55/25) ≈ 6.15

This is the amount the temperature of the drink is below room temperature.

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The temperature of the drink after 55 minutes is about 13.85 °C.

3 0
3 years ago
Today, Mariam wants to do no more than 120 jumping jacks for her workout in 6 minutes. She already did 30 jumping jacks. Which i
Elena-2011 [213]

Answer:

The answer is 132.

6 0
3 years ago
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0
4 years ago
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