Let x be the daily fee
0.5(48) +x = 64 is the equation,
Multiply:
24 + x = 64
Subtract:
x=40
The daily fee is $40
Hope this helps
Credit to Bob3141 (My first answer was wrong)
Answer and Step-by-step explanation:
Let x and y be two positive integers and their sum is 14:
X + y = 14
And the sum of square of this number is:
f = x2 + y2
= x2+ (14 – x)2
Differentiate with respect to x, we get:
F’(x) = [ x2 + (14 – x)2]’ = 0
2x + 2(14-x)(-1) = 0
2x +( 28 – 2x)(-1) = 0
2x – 28 +2x = 0
2x + 2x = 28
4x = 28
X = 7
Hence, y = 14 – x = 14 -7 = 7
Now taking second derivative test:
F”(x) > 0
For x = y = 7,f reaches its maximum value:
(7)2 + (7)2 = 49 + 49
= 98
F at endpoints x Є [ 0, 14]
F(0) = 02 + (14 – 0)2
= 196
F(14) = (14)2 + (14 – 14)2
= 196
Hence the sum of squares of these numbers is minimum when x = y = 7
And maximum when numbers are 0 and 14.
Answer:
x = 5
Step-by-step explanation:
12x - 6 + 6 = 54 + 6
12x = 60
12/12 = 60/12
X = 5
Answer:
b. How many ways arc there to go 12 miles?
≡ p(12) = 25
c. How many ways arc there to go 20 miles?
≡ p(20) = 131
d. How many ways arc there to go 22 miles?
≡p(22) 199
Step-by-step explanation:
a) supposed you walked for the first hour. Then you would have travelled 3 miles. if you jogged you would have covered 5miles and if you run you would have covered 10miles. now you have to decide how to run the rest miles from the n miles.
Thus, the number of ways one can cover n miles will be given by the recurrence relation
p(n) = p( n-3) + p( n-5) + p( n - 10)
now to solve the rest of the question, let us make a table which provides the number of ways for n = 1 to 22.
check the attachment for the table
b. How many ways arc there to go 12 miles?
≡ p(12) = 25
c. How many ways arc there to go 20 miles?
≡ p(20) = 131
d. How many ways arc there to go 22 miles?
≡p(22) 199