Explain solving systems of equations using substition?

1 answer:

8 0

when solving a system of equations the difference between that and elimination is the when you're using the Elimination u have to first multiply the numbers but when substituting it's different unlike the Elimination this is all ik and can u mark me brainliest?

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1) If a die is rolled once, determine the probability of rolling a 4: Rolling a 4 is an event with 1 favorable outcome (a roll of 4) and the total number of possible outcomes is 6 (a roll of 1, 2, 3, 4, 5, or 6). Thus, the probability of rolling a 4 is $\frac{1}{6}$ .

If a die is rolled once, determine the probability of rolling at least a 4: Rolling at least 4 is an event with 3 favorable outcomes (a roll of 4, 5, or 6) and the total number of possible outcomes is again 6. Thus, the probability of rolling at least a 4 is $\frac{3}{6}$ = $\frac{1}{2}$ .

<h3>Here are two more examples: </h3>

If a coin is flipped twice, determine the probability that it will land heads both times:

Favorable outcomes: 1 -- HH

Possible outcomes: 4 -- HH, HT, TH, TT

Thus, the probability that the coin will land heads both times is $\frac{1}{4}$ .

If Dan grabs one sock from a drawer containing 3 white socks, 4 blue socks, and 5 yellow socks, what is the probability that he will grab a white sock?

Favorable outcomes: 3 (3 white socks)

Possible outcomes: 12 (3 white socks + 4 blue socks + 5 yellow socks)

Thus, the probability that Dan will grab a white sock is $\frac{3}{12}$ = $\frac{1}{4}$ .