The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is 
seconds
So, the time required for 200 wing beat 
seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...
So, the time required for one wing beat is 5 milliseconds.
Answer:
x=4/3
Step-by-step explanation:
In pic
(hope this helps can I pls have brainlist (crown)☺️)
If those two are your only choices then the answer is
none of the above.
<em>Attached is a cumulative frequency table for your data.</em> If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong.
The answer is then none of the above or find one that matches the table attached.
Answer:
The answer is A. 4+y^2/2y^2
