Answer:
The time interval when
is at 
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between 
The schematic free body graphical representation of the above illustration was attached in the file below and the point when
is at 4 is obtained in the parabolic curve.
So,
is at 
Taking the integral of the time interval in order to determine the distance; we have:
distance = 
= 
= By using the Scientific calculator notation;
distance = 106.109 m
Answer:
h(5) = -22
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
h(x) = -5x + 3
h(5) is x = 5
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function]: h(5) = -5(5) + 3
- Multiply: h(5) = -25 + 3
- Add: h(5) = -22
92 can be rounded to 90
68 can be rounded to 70
90 x 70 = 6300
Ok...we got 250 people
30% are French, 35% are Americans, 20% are Germans....thats 85%.
This means 15% are from other countries
3 not from other countries...
0.85 * 0.85 * 0.85 = 0.6
0.6(250) = 150 students <===
Answer:
Sorry i need points to ask a question sorry dont report pos
Step-by-step explanation: