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3 years ago

6

An object is moving at a speed of 11 yards every 6 months. Express this speed in centimeters per hour. Round your answer to the

nearest hundredth.

1 answer:

lawyer [7]3 years ago

4 0

Answer:

0.23 centimeters per hour

Step-by-step explanation:

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Help asap! will award brainly and pls explain!

cluponka [151]

This is a right angle triangle.

So, by Pythagoras theorem,

√(32^2+20^2) = x

or √(1024+400) = x

or √1424 = x

or <em>37.74 = x</em>

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2 years ago

A candle is 9 inches long. Ronnie lights the candle and records the height of the candle, y inches, for x hours.

DochEvi [55]

In the future, please post the full problem with all included instructions. After doing a quick internet search, I found your problem listed somewhere else. It mentions two parts (a) and (b)

Part (a) asked for the equation of the line in y = mx+b form

That would be y = -2x+9

This is because each time y goes down by 2, x goes up by 1. We have slope = rise/run = -2/1 = -2. This indicates that the height of the candle decreases by 2 inches per hour. The slope represents the rate of change.

The initial height of the candle is the y intercept b value. So we have m = -2 and b = 9 lead us from y = mx+b to y = -2x+9

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Part (b) then asks you to graph the equation. Because this is a linear equation, it produces a straight line. We only need 2 points at minimum to graph any line. Let's plot (0,9) and (1,7) on the same xy grid. These two points are the first two rows of the table. Plot those two points and draw a straight line through them. The graph is below

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2 years ago

Whats the equation of the line that passes threw -4,4 and is parrell to the line y=1/2-4

vovangra [49]

Answer:

$y=\frac{1}{2}x+6$

Step-by-step explanation:

Given:

The equation of the known line is:

$y=\frac{1}{2}x-4$

A point on the unknown line is (-4, 4)

Now, since the two lines are parallel, their slopes must be equal.

Now, slope of the known line is the coefficient of 'x' which is $\frac{1}{2}$ .

Therefore, the slope of the unknown line is also $m=\frac{1}{2}$

Now, for a line with slope 'm' and a point on it $(x_1,y_1)$ is given as:

$y-y_1=m(x-x_1)$

Here, $m=\frac{1}{2}, x_1=-4,y_1=4$ . Therefore,

$y-4=\frac{1}{2}(x-(-4))\\\\y-4=\frac{1}{2}(x+4)\\\\y-4=\frac{1}{2}x+2\\\\y=\frac{1}{2}x+2+4\\\\y=\frac{1}{2}x+6$

Hence, the equation of the unknown line is $y=\frac{1}{2}x+6$ .

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3 years ago

What is 13(n + 4 + 7m)

nikklg [1K]

Answer:

91m+13n+52

Step-by-step explanation:

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3 years ago

Unit 8: Right Triangles & Trigonometry<br> Homework 2: Special Right Triangles

Kamila [148]

Answer:

17. z=39/sin45= $78/\sqrt{2}$

y=39/tan60= $39/\sqrt{3}$

x=y/sin60= $78/\sqrt{3}$

19. x= $6\sqrt{3}/tan60$ =6

y=2x=12

z= $\sqrt{2}y=12\sqrt{2}$

Step-by-step explanation:

17.

because:sin45=39/z

so: z=39/sin45= $78/\sqrt{2}$

then: tan60=39/y

so: y=39/tan60= $39/\sqrt{3}$

last: sin60=y/x

so: x=y/sin60= $78/\sqrt{3}$

19.

because: tan60= $6\sqrt{3}$ /x

so: x= $6\sqrt{3}/tan60$ =6

then: sin30=x/y

so: y=x*sin30=2x=12

last: sin45=y/z

so: z=sin45*y= $\sqrt{2}y=12\sqrt{2}$

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2 years ago

Read 2 more answers