Answer:
78
Step-by-step explanation:
Evaluate 6 (2 x^2 - 5) where x = -3:
6 (2 x^2 - 5) = 6 (2×(-3)^2 - 5)
Hint: | Evaluate (-3)^2.
(-3)^2 = 9:
6 (2×9 - 5)
Hint: | Multiply 2 and 9 together.
2×9 = 18:
6 (18 - 5)
Hint: | Subtract 5 from 18.
| 1 | 8
- | | 5
| 1 | 3:
6×13
Hint: | Multiply 6 and 13 together.
6×13 = 78:
Answer: 78
Answer:
P(X < 80) = 0.89435.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

P(X < 80)
This is the pvalue of Z when X = 80. So



has a pvalue of 0.89435.
So
P(X < 80) = 0.89435.
Do 9:00 A.M. minus 26 minutes and your awnser is 8:34 A.M.
The vertex (minimum) of the quadratic ax² +bx +c is located at x=-b/(2a). This means the minimum value of f(x) will be found at x = -3/(2*1) = -1.5.
Since the vertex of the quadratic is less than 0, the maximum value of the quadratic will be found at x=2, the end of the interval farthest from the vertex.
On the given interval, ...
the absolute minimum value of f is f(-1.5) = ln(1.75) ≈ 0.559616
the absolute maximum value of f is f(2) = ln(14) ≈ 2.639057