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masha68 [24]
3 years ago
15

PLZ HELP I’M TIMED!! I’LL GIVE BRAINLIEST- FIND THE VALUE OF Y

Mathematics
1 answer:
Galina-37 [17]3 years ago
8 0

Answer:

131

Step-by-step explanation:

25+24=49

180-49=131

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Determine the measure of ∠DBC. answers: 1) 130° 2) 115° 3) 230° 4) 65°
Norma-Jean [14]

Answer:

65 degrees

Step-by-step explanation:

65 degrees

it is 65 because of the vector relationship: 30 + 100 = 130. 130/2=65 degrees

5 0
3 years ago
Read 2 more answers
Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0
2 years ago
PLEASE HELP AND SHOW WORK!!
Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

7 0
2 years ago
Triangle ABC has perimeter 22 cm.
Serggg [28]

Answer:

Step-by-step explanation:

A = 8 cm

B = 5 cm

C = 22 - 8 - 5 = 9 cm

Use the Pythagreom Theroem (a^2 + b^2 = c^2) if the two sides are equal to one another than it is a right triangle.

8^2 + 5^2 = 9^2

64 + 25 = 81

89 = 81

89 does not equal 81, so this is not a right triangle.

3 0
2 years ago
You buy 4 bags of sand and 3 bags of pea gravel for $24. In a second purchase (at the same prices), you buy 2 bags of sand for $
Kazeer [188]

Answer:

x = $3

y = $4

Step-by-step explanation:

We need to know the prices of gravel and peas. We can find the price by using equations and graphing them.

Let X be the price of the sand

Be and the price of pea gravel

In the first purchase we have:

4x + 3y = 24

In the second purchase we have

2x = 6

Both relations represent the equation of a line. In the graphic shown, these lines are drawn. In this case the interception between both lines represents the price of each product, and the solution of the problem. You can see that the lines intersect at point (3 4). This means that the price of each bag of sand is $ 3, and the price of a bag of pea gravel is $ 4.

6 0
3 years ago
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