Answer:
It should be 46.20
Step-by-step explanation:
You're rounding to the nearest hundredth. So you have 46.1979 to start out with. Then you count 2 places so you end at the 1st 9. Well, behind the 9 is a 7 so you round up and get 20
In y = mx + b form, which is what ur equation is in, the y int can be found in the b position
y = mx + b
y = x + 6
as u can see, the number in the b position, ur y int, is 6 <==
A' = (-2, 1)
B' = (1, 0)
C' = (-1, 0)
Given:
Atul has 
lb of candy.
Jose has 
lb of candy.
Maria has 
lb less than Jose.
To find:
How many more pounds of candy does Atul have than Maria?
Solution:
Since, Maria has lb less than Jose, therefore
Maria has = 
lb
Maria has = 
lb
Maria has = 
lb
Difference between the candies Atul and Maria have.
Difference = 
lb
Difference = 
lb
Difference = 
lb
Therefore, Atul have lb of candy more than Maria.
quadratic formula:
x = <u>-b ± √(b² - 4ac)</u>
2a
7x² - x = 7
subtract 7 from both sides:
7x² - x - 7 = 0
plug values into the quadratic formula:
x = <u>-(-1) ± √((-1)²- 4(7)(-7))</u>
2(7)
simplify:
x = <u>1 ± √(197)</u>
14
