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3 years ago

What division equation is related to 4*6=24

Mathematics

2 answers:

kvv77 [185]3 years ago

8 0

Maybe something like 24/4=6. so sorry if I'm incorrect.

Evgen [1.6K]3 years ago

8 0

Answer:

6 = 24 / 4 and 4 = 24 / 6

Step-by-step explanation:

We have the equation 4*6 = 24. To make this division, we can divide by something so that the left side is an integer, and the right side is a division equation. If we divide by 4, we get 6 = 24 / 4. Or, we could divide by 6 to get 4 = 24 / 6. So, these are the two answers.

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Goshia [24]

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4 years ago

What is the slope of this line

Elenna [48]

Answer:

Step-by-step explanation:

rise/run = slope

As it goes to the left or adds by one, it goes up by 4

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3 years ago

Read 2 more answers

Candidates running for office are handing out items to voters. Every 6th voter gets a button. Every 7th voter gets a sticker.

e-lub [12.9K]

The computation shows that the voter is the first to receive both items is A. the 42nd voter.

<h3>How to compute the value?</h3>

From the information, the candidates running for office are handing out items to voters as every 6th voter gets a button while every 7th voter gets a sticker.

Therefore, it should be noted that the least common multiple of both 6 and 7 is 42. Therefore, the voter is the first to receive both items is the 42nd voter.

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brainly.com/question/4658834

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2 years ago

6. You roll a 6 sided die and flip a coin. What is the

MakcuM [25]

Answer:

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2 years ago

A statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after

lana [24]

Answer:

95% confidence interval estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

(a) Lower Limit = 0.486

(b) Upper Limit = 0.624

Step-by-step explanation:

We are given that a statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after receiving their bachelor's.

She took a random sample of 200 graduates from the class of 1979 and determined their occupations in 1989. She found that 111 persons were still employed primarily as engineers.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of persons who were still employed primarily as engineers = $\frac{111}{200}$ = 0.555

n = sample of graduates = 200

p = population proportion of engineers

<em>Here for constructing 95% confidence interval we have used One-sample z proportion test statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.555-1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } }$ , $0.555+1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } }$ ]

= [0.486 , 0.624]

Therefore, 95% confidence interval for the estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

7 0

3 years ago