1/2 × 5 2/3 × 3 = 5
the 2's cancel giving you 5 × 1/3 × 3
then the 3's cancel giving you 5 × 1
and 5 × 1 is 5.
Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
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* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
Answer:
5
Step-by-step explanation:
-1+(1)= 0
0+(4)=4
1+4=5
Answer:
Yes its a quadrilateral
Step-by-step explanation:
It has 4 sides