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Pavel [41]
3 years ago
7

5. How many moles are in 58.6 L of Nitrogen gas (N.) at STP?

Chemistry
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

2.6166 moles

Explanation:

stp means: T=273k   p=101.3kpa

R= 8.31(constant)       v=58.6  

using the ideal gas law; pv=nRt

                                        101.3 x 58.6 = n x 8.31 x 273

                                         n= (101.3 x 58.6)\(8.31 x 273)

                                         n= 2.6166moles

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Answer:

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Explanation:

In this problem, the temperature stays constant. The volume and pressure change, so we use Boyle's Law. This states that the pressure of a gas is inversely proportional to the volume. The formula is:

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\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}= P_2

The units of liters cancel.

\frac {25.0  * 2.05 \ atm }{14.5 }=P_2

\frac {50.25\  atm }{14.5 }=P_2

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The original values of volume and pressure have 3 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 3.53448276

The 4 in the thousandth place (in bold above) tells us to leave the 3 in the hundredth place.

3.53 \ atm \approx P_2

The new pressure is approximately <u>3.53 atmospheres.</u>

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