2AgNO3+K2CrO4⇒Ag2CrO4(s)+2KNO3
Hence by mixing 0.0024M AgNO3 and 0.004M
K2CrO4, we will have Ag2CrO4 which is precipitated out and leave us with
0.0024M KN03 which is mixed with (0.004-0.0024/2)M, it can be 0.0028M, of K2Cr04
The balanced equation of NaOH and H2SO4 would be:
2NaOH + H2SO4 = Na2SO4 + 2H2O
To determine the concentration of NaOH, we first find the moles of NaOH used in the reaction. We start with the the concentration and volume of H2SO4. We do as follows:
2.00 M H2SO4 ( 0.25 L ) = 0.5 mol H2SO4
0.5 mol H2SO4 ( 2 mol NaOH / 1 mol H2SO4) = 1 mol NaOH
Molarity = 1 mol NaOH / 2.00 L NaOH solution = 0.5 M NaOH solution
Answer:
The symbol used to separate the product from each other or reactants from each other is 'plus' (+) .
Explanation:
In chemical equation the symbol used to separate the product from each other or reactants from each other is 'plus' (+) .
While the symbol used to separate the reactant and product from each other is '→'
For example:
Consider the following reaction.
2H₂ + O₂ → 2H₂O
Two moles of hydrogen react with one mole of oxygen to form two moles of water. The both reactant hydrogen and oxygen are separated by the + while reactant and products are separated by → .
At the center of every atom lies a small, dense "nucleus" that is positively charged.
Atom is the smallest unit of matter. It is made up of electrons, protons and neutrons. Electrons are negatively charged particles that are found scattered in different energy levels outside the nucleus. Protons are positively charged particles present inside the nucleus. Neutrons do not carry charge and found inside the nucleus. Thus, protons and neutrons make up the nucleus of an atom. Since, protons are positively charged and neutrons are uncharged particles, the charge of nucleus becomes positive.
<u>Answer:</u> No crystals of potassium sulfate will be seen at 0°C for the given amount.
<u>Explanation:</u>
We are given:
Mass of potassium nitrate = 47.6 g
Mass of potassium sulfate = 8.4 g
Mass of water = 130. g
Solubility of potassium sulfate in water at 0°C = 7.4 g/100 g
This means that 7.4 grams of potassium sulfate is soluble in 100 grams of water
Applying unitary method:
In 100 grams of water, the amount of potassium sulfate dissolved is 7.4 grams
So, in 130 grams of water, the amount of potassium sulfate dissolved will be 
As, the soluble amount is greater than the given amount of potassium sulfate
This means that, all of potassium sulfate will be dissolved.
Hence, no crystals of potassium sulfate will be seen at 0°C for the given amount.