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zimovet [89]
4 years ago
6

The answer that he gave was wrong

Chemistry
1 answer:
sergejj [24]4 years ago
6 0
Ok...what was the question


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A compound decomposes by a first-order process. if 25.0% of the compound decomposes in 60.0 minutes, the half-life of the compou
Tom [10]
Answer:<span>d. 145 minutes
</span>
Half-life is the time needed for a radioactive to decay half of its weight. The formula to find the half-life would be:

Nt= N0 (1/2)^ t/h

Nt= the final mass
N0= the initial mass
t= time passed
h= half-life

If 25.0% of the compound decomposes that means the final mass would be 75% of initial mass. Then the half-live for the compound would be:
Nt= N0 (1/2)^ t/h
75%= 100% * (1/2)^ (60min/h)
3/4= 1/2^(60min/h)
log2 3/4 = log2 1/2^(60min/h)
0.41503749928 = -60min/h
h= -60 min / 0.41503749928= 144.6min 
3 0
3 years ago
What dangerous element does Feista Wear contain
strojnjashka [21]

uranium oxide

Hope This Helps!       Have A Nice Day!!

3 0
3 years ago
Read 2 more answers
How much heat does it take to melt 5.0g solid copper?
Leya [2.2K]

Answer:

Q=1.04kJ

Explanation:

Hello,

In this case, for latent heat (phase change) we need to consider the enthalpy associated with the involved process, here, melting or fusion; thus, the enthalpy of fusion of copper is 13.2 kJ/mol, therefore, the heat is computed as:

Q=m\Delta H_{fus}

Nevertheless, since the given enthalpy is per mole of copper, we need to use its atomic mass to perform the correct calculation as follows:

Q=5.0g*\frac{1mol}{63.54}* 13.2\frac{kJ}{mol}\\ \\Q=1.04kJ

Which is positive as it needs to be supplied to the system.

Best regards.

5 0
3 years ago
The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25
sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL =  4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal

1 calorie = 4.184 J

Q=\frac{340,956.75}{4.184} J = 81,490.62 J

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

5 0
3 years ago
A catalytic effect or acceleration of a reaction can occur in the ________ of an enzyme.
Galina-37 [17]
The active site of the enzyme.
6 0
3 years ago
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