An archer has a mean distance of 1.6 inches and a MAD distance of 1.3 inches in the first round. In the second round, the archer
's arrows are farther from the center but are more consistent. What values for the mean and MAD would fit this description for the second round?
1 answer:
I think it’s 1.5 cause it shows it
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Hi friend,
f(x) = x²
g(x) = x+6
f(0) = 0² =0
g ( f(0) ) = f(0) +6
= 0+6 = 6
Hope this helps you!
Answer:
1.5
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and 9
Answer:
D
Step-by-step explanation:
cuz its a 90° angle
Answer:
⇒y=32x+18
Step-by-step explanation:
Answer:
x>7
Step-by-step explanation:
x-3>4
Add 3 to both sides
x>7
Hope it helped!
