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stich3 [128]
3 years ago
11

An archer has a mean distance of 1.6 inches and a MAD distance of 1.3 inches in the first round. In the second round, the archer

's arrows are farther from the center but are more consistent. What values for the mean and MAD would fit this description for the second round?
Mathematics
1 answer:
schepotkina [342]3 years ago
7 0
I think it’s 1.5 cause it shows it
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lora16 [44]

Answer:

1st, 3rd and 4th

Step-by-step explanation:

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6 0
4 years ago
According to a​ report, 67.5​% of murders are committed with a firearm. ​(a) If 200 murders are randomly​ selected, how many wou
kolezko [41]

Answer: The answer is 135 murders.

Step-by-step explanation: The report tells us that statistically 67.5% of murders are committed using a firearm. It follows therefore that in a sample of 200 randomly selected murders, one would expect that 67.5% of those would be by a firearm. \frac{67.5}{100} * 200 = 135.

It would certainly be higher that the expected value based on previous data collected but it would not be unusual because one sample may have a higher than "normal" amount of murders by firearm. Statistics aren't going to be exact for every sample.

8 0
3 years ago
What is 3 3/8 +3 1/2 using common denominator
horrorfan [7]
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8 0
3 years ago
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5 0
3 years ago
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The table represents the start of the division of 15x3 + x2 - 3x + 2 by 3x + 2.
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The result of dividing 15x^{3}+x^{2}-3x+2 by 3x+2 is 5 x^{2} -3x+1 with no remainder. Please check the step by step procedures in the picture attached.
We can conclude that:
The quotient of the division is 5 x^{2} -3x+1
The remainder of the division is 0
The divisor is 3x+2
The dividend is 15x^{3}+x^{2}-3x+2

4 0
4 years ago
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