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Alik [6]
3 years ago
5

Mark drank 3 2/5 cups of orange jucie in the morning and 2 1/5 cups in the afternoon. How much orange jucie did mark drink in al

l?
Mathematics
1 answer:
Alinara [238K]3 years ago
5 0
Solutions 

1) Convert mixed fractions into improper fractions. 

\frac{17}{5}+ \frac{11}{5}

= ((17 * 5) + (11 * 5)) / (5 * 5)

= (85 + 55) / 25

= 140/25

= 28/5

5  \frac{3}{5}
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Two smoothies and an ice cream cone cost $7.50. Three smoothies and two ice cream cones cost $12. Calculate the cost of a smooth
anygoal [31]

Answer:

Smoothie = 3

Ice cream = 1.5

Step-by-step explanation:

2s + i = 7.5

3s + 2i = 12

subtract the equations

(3s + 2i) - (2s + i) = s + i

s + i = 4.5

2s + i = 7.5,  so s must equal 3 (7.5 - 4.5)

If s = 3, then i is 1.5 (4.5 - 3.5)

To check, plug 3 and 1.5 into s and i.

2(3) + 1.5 = 7.5

6 + 1.5 = 7.5

7.5 = 7.5

3(3) + 2(1.5) = 12

9 + 3 = 12

12 = 12

5 0
3 years ago
List all the factor pairs of 40
Zarrin [17]
2x20
1x40
4x10
5x8

All integers these multiply to 40
6 0
3 years ago
Read 2 more answers
On his way to work, a man notices that 9 of the 16 traffic lights are green. Is there statistical significance to say that these
olasank [31]
Yes because the results are unlikely to occur by chance, is what I think .
6 0
3 years ago
Read 2 more answers
The wholesale price for a desk is $102. A certain furniture store marks up the wholesale price by 25%. Find the price of the des
denpristay [2]

Answer:

I guess $197.06

Step-by-step explanation:

8 0
2 years ago
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
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