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yulyashka [42]
3 years ago
5

How can you use transformations to graph this function? y=3.75 +2 Explain your steps.

Mathematics
1 answer:
mina [271]3 years ago
3 0

Answer:

Sketch the graph of y=7^x

Reflect the graph across the y-axis to show the function y=7^-x

Stretch the graph vertically by a factor of 3 to show the function y=3*7^-x            

Shift the graph up 2 units to show the function y=3*7^-x+2

Step-by-step explanation:

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Graph the equation by translating Y =|x|. Y=|x+1|-3
goldenfox [79]

Answer:

look at the graph i made with desmos, i just plugged the equation in.

Step-by-step explanation:

6 0
3 years ago
What is the correct order of the following numbers from least to greater?<br> 2/3, -0.6, 0.65, 4/5
ExtremeBDS [4]
We can either convert them to decimals or to fractions
if decimals
2/3=0.66666666
4/5=8/10=0.8
so the order is
-0.6, 0.65, 0.66, 0.8 or
-0.6, 0.65, 2/3, 4/5

if conver to fractions then
since -0.6 is negative, it is smallest, no need to convert
0.65=65 hundreths=65/100
2/3=66/99=prety close
4/5=8/10=80/100
order is
-0.6, 65/100, 66/99, 80/100 or
-0.6, 0.65, 2/3, 0.8
5 0
3 years ago
Read 2 more answers
My expectation from my teacher.
vovangra [49]
I would like to have a patient and good teacher,who is not angry or stressed,or give us lots of homeworks.

Hope I helped u :)
8 0
3 years ago
What is a simpler form of the expression? -3(-4y+3)+7y please explain, i don’t understand it.
Pavlova-9 [17]

Answer:

19y - 9

Step-by-step explanation:

We can use the acronym PEMDAS. First, we need to calculate -3(-4y+3) by distributing. This is -3 * (-4y) + (-3) * 3 = 12y - 9 so the expression becomes 12y - 9 + 7y. Next, we need to combine like terms. 12y and +7y are like terms since they both have y so combining them gives us 12y + 7y = 19y. -9 stays by itself since there are no other constants so the final answer is 19y - 9.

5 0
4 years ago
Read 2 more answers
How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
2 years ago
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