The length of the shorter rope is 20 cm.
<h3>How to find the original length of the rope using ratio?</h3>
He cut a rope into two pieces with lengths having a ratio of 5 to 2.
The shorter piece is 70 cm long.
The length of the original rope can be calculated as follows:
The ratio of the length of the rope is as follows;
5 : 2
let
x = length of the original rope
Therefore,
length of shorter piece = 2 / 7 × 70
length of shorter piece = 2 / 7 × 70
length of shorter piece = 140 / 7
length of shorter piece = 20 cm
Therefore, the length of the shorter rope is 20 cm.
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Answer:
x = 45
Step-by-step explanation:
Corresponding sides of similar triangles will be in same ratio.

Cross multiply
x*28 = 20*(x+18) {Use distributive method}
28x = 20x + 360
28x - 20x = 360
8x = 360
x = 360/8
x = 45
The area of an object is found by multiplying the length by the width, so to solve your problem, multiply 8*4 to get 32.
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

2.

3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Answer:
first do 9x40 and get your answer then do 18x3 and get that answer and then add to do answers together