59m • tan 46 is -123.110198 meters.
The value of x is less than or equal to 2.25.
<h2>Linear system</h2>
It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.
<h3>Simplification</h3>
Simplification is to make something easier to do or understand and to make something less complicated.
Given
The expression is 47.75 + x ≤ 50.
<h3>To find</h3>
The value of x.
<h3>How to find the value of x?</h3>
The expression is 47.75 + x ≤ 50.
On simplifying,
47.75 + x ≤ 50
x ≤ 50 - 47.75
x ≤ 2.25
Thus, the value of x is less than or equal to 2.25.
More about the linear system link is given below.
brainly.com/question/20379472
Answer:
<h3><u>Option 1</u></h3>
Earn $50 every month.
- Let x = number of months the money is left in the account
- Let y = the amount in the account
- Initial amount = $1,000

This is a <u>linear function</u>.
<h3><u>Option 2</u></h3>
Earn 3% interest each month.
(Assuming the interest earned each month is <u>compounding interest</u>.)
- Let x = number of months the money is left in the account
- Let y = the amount in the account
- Initial amount = $1,000

This is an <u>exponential function</u>.
<h3><u>Table of values</u></h3>
<u />

From the table of values, it appears that <u>Account Option 1</u> is the best choice, as the accumulative growth of this account is higher than the other account option.
However, there will be a point in time when Account Option 2 starts accruing more than Account Option 2 each month. To find this, graph the two functions and find the <u>point of intersection</u>.
From the attached graph, Account Option 1 accrues more until month 32. From month 33, Account Option 2 accrues more in the account.
<h3><u>Conclusion</u></h3>
If the money is going to be invested for less than 33 months then Account Option 1 is the better choice. However, if the money is going to be invested for 33 months or more, then Account Option 2 is the better choice.
A is the correct answer
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