-1 Let's say the set of downs starts at the 20 yard line (maybe the kicking team kicked deep, the receiving team took a knee and so play starts at the 20).
Ok - we're at the 20. First down - they advance 5 yards. So we're now at the 25. We can write that mathematically as:
20
+
5
=
25
So the second play they get sacked deep and lose 6 yards. So we subtract 6:
25
−
6
=
19
So what's the change in yardage for the 2 plays? We are on the 19 and started at the 20, so we can write:
19
−
20
=
−
1
and this makes sense because we know we advanced 5 and fell back 6
Answer:
The relation is a function!
Your Domain should be...
{-1, 1, 7, 9}
Your Range should be...
{-1, 8, 9}
WHY?
Your domain is always your x-coordinates, which are the first coordinates in a pair.
Your range is always your y-coordinates, which are the second coordinates in a pair.
When listing the points, it's important to remain a relation CANNOT be a function if the x's repeat, so luckily, they do not repeat.
Also, when listing points for your range, remember, if they repeat, you should only count one of the numbers, as you can see from the answer, there was two nines, but instead I put one.
ANSWER

EXPLANATION
The diagram represents the net of a rectangular prism.
The dimensions are,


and

The total surface area of a rectangular prism is given by:

We substitute the values to obtain,


Hi there!
The answer would be A. m = 45h
Hope this helps
Answer:
455 or 680, depending
Step-by-step explanation:
If we assume the three choices are different, then there are ...
15C3 = 15·14·13/(3·2·1) = 35·13 = 455
ways to make the pizza.
___
If two or three of the topping choices can be the same, then there are an additional ...
2(15C2) +15C1 = 2·105 +15 = 225
ways to make the pizza, for a total of ...
455 + 225 = 680
different types of pizza.
__
There is a factor of 2 attached to the number of choices of 2 toppings, because you can have double anchovies and tomato, or double tomato and anchovies, for example, when your choice of two toppings is anchovies and tomato.
_____
nCk = n!/(k!(n-k)!)