False because the atoms are what helps the liquid in the container
Beryllium has two inner shell electrons
The answer is Joule. Kilograms and Grams is a unit for weight
Answer : The enthalpy change during the reaction is -6.48 kJ/mole
Explanation :
First we have to calculate the heat gained by the reaction.
![q=m\times c\times (T_{final}-T_{initial})](https://tex.z-dn.net/?f=q%3Dm%5Ctimes%20c%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29)
where,
q = heat gained = ?
m = mass of water = 100 g
c = specific heat = ![4.04J/g^oC](https://tex.z-dn.net/?f=4.04J%2Fg%5EoC)
= final temperature = ![26.6^oC](https://tex.z-dn.net/?f=26.6%5EoC)
= initial temperature = ![25.0^oC](https://tex.z-dn.net/?f=25.0%5EoC)
Now put all the given values in the above formula, we get:
![q=100g\times 4.04J/g^oC\times (26.6-25.0)^oC](https://tex.z-dn.net/?f=q%3D100g%5Ctimes%204.04J%2Fg%5EoC%5Ctimes%20%2826.6-25.0%29%5EoC)
![q=646.4J](https://tex.z-dn.net/?f=q%3D646.4J)
Now we have to calculate the enthalpy change during the reaction.
![\Delta H=-\frac{q}{n}](https://tex.z-dn.net/?f=%5CDelta%20H%3D-%5Cfrac%7Bq%7D%7Bn%7D)
where,
= enthalpy change = ?
q = heat gained = 23.4 kJ
n = number of moles barium chloride = ![\frac{\text{Mass of barium chloride}}{\text{Molar mass of barium chloride}}=\frac{20.8g}{208.23g/mol}=0.0998mole](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BMass%20of%20barium%20chloride%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20barium%20chloride%7D%7D%3D%5Cfrac%7B20.8g%7D%7B208.23g%2Fmol%7D%3D0.0998mole)
![\Delta H=-\frac{646.4J}{0.0998mole}=-6476.95J/mole=-6.48kJ/mole](https://tex.z-dn.net/?f=%5CDelta%20H%3D-%5Cfrac%7B646.4J%7D%7B0.0998mole%7D%3D-6476.95J%2Fmole%3D-6.48kJ%2Fmole)
Therefore, the enthalpy change during the reaction is -6.48 kJ/mole