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melisa1 [442]
3 years ago
8

The temperature of 300 milliliters of a gas at 400K is increased to 800K, pressure remaining constant. What will the new volume

of gas be?
Chemistry
1 answer:
Annette [7]3 years ago
4 0

Answer:

V₂ = 600 mL

Explanation:

Given data:

Initial volume = 300 mL

Initial temperature = 400 K

Final temperature = 800 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 300 mL × 800 K / 400 k

V₂ = 240000 mL.K / 400  K

V₂ = 600 mL

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Answer:

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2 years ago
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A gas occupies the volume of 215ml at 15C and 86.4kPa?
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Answer:

About 0.1738 liters

Explanation:

Using the formula PV=nRT, where p represents pressure in atmospheres, v represents volume in liters, n represents the number of moles of ideal gas, R represents the ideal gas constant, and T represents the temperature in kelvin, you can solve this problem. But first, you need to convert to the proper units. 215ml=0.215L, 86.4kPa is about 0.8527 atmospheres, and 15C is 288K. Plugging this into the equation, you get:

0.8527\cdot 0.215=n \cdot 0.0821 \cdot 288\\n\approx 7.754 \cdot 10^{-3}

Now that you know the number of moles of gas, you can plug back into the equation with STP conditions:

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27.5 g . 1mol / 44 g = 0.625 moles

We need density of O₂ to determine mass and then, the moles.

O₂ density = O₂ mass / O₂ volume

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1 atm . V = 1.21 moles . 0.082 . 273K

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