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melisa1 [442]
3 years ago
8

The temperature of 300 milliliters of a gas at 400K is increased to 800K, pressure remaining constant. What will the new volume

of gas be?
Chemistry
1 answer:
Annette [7]3 years ago
4 0

Answer:

V₂ = 600 mL

Explanation:

Given data:

Initial volume = 300 mL

Initial temperature = 400 K

Final temperature = 800 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 300 mL × 800 K / 400 k

V₂ = 240000 mL.K / 400  K

V₂ = 600 mL

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The molarity of KCl has been given as 4.0 M
This means that in 1 L of KCl solution, there are 4 moles dissolved.
We have been asked to find the volume of the solution if there are 8.0 moles of solute.
If 4 moles are in - 1 L of solution
Then 8 moles of solute are in - 1/4 x 8 = 2 L solution
Volume of KCl solution is 2 L.
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Rank the following substances in order from most soluble in water to least soluble in water: methane, CH4; 2-butanol, C4H9OH; po
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Answer:

Arranged in order of most soluble to least soluble in water:

KCl > CH_{4}  > C_{4} H_{9} OH > C_{3}H_{8}

Explanation:

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Non-polar molecules would be dissolved by non-polar solvents.

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0.0005411
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4 0
3 years ago
If air has a dry-bulb temperature of 2°C
Allisa [31]

Answer:

The relative humidity is 36%.

Explanation:

Relative humidity is the measure of ratio of actual vapor density to saturated vapor density in a given system. So there are different ways to measure the relative humidity in the atmosphere. One of the common ways is to measure using Psychrometer. In this instrument, two different thermometers are used as measuring device. One of the thermometer measures the humidity in dry air and another in wet air. So the difference of the temperature of dry and wet air bulb will be related to determine the relative humidity percentage. The formula to determine the relative humidity using this method is as below.

Relative humidity=\frac{(e_{w}-[N*(1+0.00115*T_{w}*(T_{d}-T_{w}))])*100}{e_{d} }

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And,

e_{w}=6.112*e^{[\frac{(17.502*T_{w} )}{(240.97+T_{w} )}]}

Here e =2.718, T_{d} and T_{w} are the temperature at dry bulb and wet bulb temperatures, respectively.

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3 years ago
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