2 years ago

If a regular polygon has exterior angles that measure approximately 17.14º each, how many sides does the polygon have?

Mathematics

1 answer:

mr Goodwill [35]2 years ago

6 0

Exterior angles for n sides = 360/n = 17.14, n = 360/17.14 = <span>21 sides</span>

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How do I solve -2m=16m-9

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Second, add '-2m - 16m' to get '-18m'.
$-18m = -9$
Third, divide both sides by '-18'.
$m = \frac{-9}{-18}$
Fourth, change the fraction into a negative.
$m = \frac{9}{18}$
Fifth, find the GCF of 9 and 18.
The GCF is 9.
Sixth, divide the numerator by the GCF.
$9$ ÷ $9 = 1$
Seventh, divide the denominator by the GCF.
$18$ ÷ $9 = 2$
Eighth, rewrite the fraction in simplest form.
$m = \frac{1}{2}$

Answer as fraction: $m = \frac{1}{2}$
Answer as decimal: $m = 0.5$