Question

A ball is dropped from a tower that is 512 feet high. Use the formula below to find height of the ball 5 seconds after it was dropped? h=512−14t2where h represents the height, in feet, and t represents the time, in seconds, after it was dropped.

Answer 1

Answer:

The height of the ball after 5 seconds is 162 ft.

Explanation:

First, replace the variable t with how many seconds the ball has dropped, which in this case is 5.

$h = 512 - 14 {t}^{2} \\ h = 512 - 14 \times {5}^{2}$

Solve.

$h = 512 - 14 \times {5}^{2} \\ h = 512 - 14 \times 25 \\ h = 512 - 350 \\ h = 162$

For a duration of 5 seconds, the ball had managed to drop 350 feet, with 162 feet left to go to touch ground level.