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djyliett [7]
3 years ago
15

how much time would it take for an airplane to reach its destination if it traveled at an average speed of 790 km/hr for a dista

nce
Physics
1 answer:
NeTakaya3 years ago
8 0
I think your question is incomplete because the distance between destination and departure point isn't given in the question

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Which is a characteristic of centripetal acceleration?
djyliett [7]

Answer:

It is directed inward, toward the center of a circle.

5 0
3 years ago
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A toy car moves around a circular track at constant speed. It suddenly doubles its speed — a change of a factor of 2. As a resul
Zigmanuir [339]

Answer:

option B

Explanation:

given,

toy car is moving in circular track

speed is doubled— a change of a factor of 2

to find change in factor of acceleration

radius doesn't change

centripetal acceleration formula

           = \dfrac{v^2}{r}

velocity is change in factor of 2

so acceleration will be change at the factor of

           = \dfrac{(2v)^2}{r}

           = 2² = 4

so the correct answer is option B

4 0
4 years ago
Please annswer will the correct letter I WILL GIVE BRAINLIEST MUST ANSWER BOTH :)
erica [24]
C  and A the first one is a bit weird but thats what i got and you cant even see it that good
3 0
3 years ago
A model rocket rises with constant acceleration to a height of 4.2 m, at which point its speed is 27.0 m/s. How much time does i
geniusboy [140]

Answers:

a) t=0.311 s

b) a=86.847 m/s^{2}

c) y=1.736 m

d) V=17.369 m/s

Explanation:

For this situation we will use the following equations:

y=y_{o}+V_{o}t+\frac{1}{2}at^{2} (1)  

V=V_{o} + at (2)  

Where:  

y is the <u>height of the model rocket at a given time</u>

y_{o}=0 is the i<u>nitial height </u>of the model rocket

V_{o}=0 is the<u> initial velocity</u> of the model rocket since it started from rest

V is the <u>velocity of the rocket at a given height and time</u>

t is the <u>time</u> it takes to the model rocket to reach a certain height

a is the <u>constant acceleration</u> due gravity and the rocket's thrust

<h2>a) Time it takes for the rocket to reach the height=4.2 m</h2>

The average velocity of a body moving at a constant acceleration is:

V=\frac{V_{1}+V_{2}}{2} (3)

For this rocket is:

V=\frac{27 m/s}{2}=13.5 m/s (4)

Time is determined by:

t=\frac{y}{V} (5)

t=\frac{4.2 m}{13.5 m/s} (6)

Hence:

t=0.311 s (7)

<h2>b) Magnitude of the rocket's acceleration</h2>

Using equation (1), with initial height and velocity equal to zero:

y=\frac{1}{2}at^{2} (8)  

We will use y=4.2 m :

4.2 m=\frac{1}{2}a(0.311)^{2} (9)  

Finding a:

a=86.847 m/s^{2} (10)  

<h2>c) Height of the rocket 0.20 s after launch</h2>

Using again y=\frac{1}{2}at^{2} but for t=0.2 s:

y=\frac{1}{2}(86.847 m/s^{2})(0.2 s)^{2} (11)

y=1.736 m (12)

<h2>d) Speed of the rocket 0.20 s after launch</h2>

We will use equation (2) remembering the rocket startted from rest:

V= at (13)  

V= (86.847 m/s^{2})(0.2 s) (14)  

Finally:

V=17.369 m/s (15)  

5 0
3 years ago
Two gliders collide on a frictionless air track that is aligned along the x axis. Glider A has an initial velocity v0 and glider
LenaWriter [7]

Answer:

Explanation:

Applying conservation of momentum

mA v0 + 0 = mA x 12v0 + mB x 92v0

11 mA = - 92mB .

mA / mB = 92 / 11

mA : mB = 92 : 11.

3 0
3 years ago
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