Answer:
I= 3.5 amps
Explanation:
Step one:
given data
rating of resistor R= 8 ohms
power P= 100W
Required
The current I
Step two
Yet this power is also given by
![P = I^2R](https://tex.z-dn.net/?f=P%20%3D%20I%5E2R)
make I subject of the formula we have
![I= \sqrt{\frac{P}{R} }](https://tex.z-dn.net/?f=I%3D%20%5Csqrt%7B%5Cfrac%7BP%7D%7BR%7D%20%7D)
substitute
![I= \sqrt{\frac{100}{8} }\\\\I=\sqrt{12.5}\\\\I= 3.5 amps](https://tex.z-dn.net/?f=I%3D%20%5Csqrt%7B%5Cfrac%7B100%7D%7B8%7D%20%7D%5C%5C%5C%5CI%3D%5Csqrt%7B12.5%7D%5C%5C%5C%5CI%3D%203.5%20amps)
This is possible due to self-discharge. Very small internal currents inevitably occur in these cells over time and they will eventually exhaust the chemistry.
The time taken by the pulse to travel from one support to the other is 0.208 s.
<h3>Given:</h3>
The mass of the cord is m = 0.65 kg.
The distance between the supports is, d = 8.0 m.
The tension in the cord is T = 120 N.
The time taken by the pulse to travel from one support to the other is given as,
![v=\frac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D)
![t=\frac{d}{v}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7Bv%7D)
Here, v is the linear velocity of a pulse. Its value is,
![v=\sqrt{\frac{T d }{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7BT%20d%20%7D%7Bm%7D%20%7D)
![v=\sqrt{\frac{120 * 8}{0.65} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B120%20%2A%208%7D%7B0.65%7D%20%7D)
![v= 38.43 m/s](https://tex.z-dn.net/?f=v%3D%2038.43%20m%2Fs)
Then,
![t=\frac{8}{38.43}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B8%7D%7B38.43%7D)
![t=0.208 s](https://tex.z-dn.net/?f=t%3D0.208%20s)
Thus, the time taken by the pulse to travel from one support to the other is 0.208 s.
Learn more about tension here:
brainly.com/question/24994188
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