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3 years ago

Please help! i need to pass this class!!

Mathematics

2 answers:

svetoff [14.1K]3 years ago

6 0

Answer:

m∠B = 54°

Step-by-step explanation:

Note: Complementary angles add up to 90°

Thus, m∠A and m∠B must add up to 90.

We can then write this equation.

x - 15 + x + 3 = 90

Simplify.

2x - 12 = 80

Add 12 to both sides.

2x = 102

x = 51

m∠B is (x + 3) , so m∠B = 51+ 3 = 54°

Just in case, let's double check. Plug 39 for x into m∠A to get

m∠A = 51 - 15 = 36

Then, plug the angle measures in.

36 + 54 = 90

90 = 90

Thus, the answer is correct.

I hope this helps! Feel free to ask any questions! :)

torisob [31]3 years ago

3 0

Angle B = 54°

Step-by-step explanation:

complimentary means they add up to 90

54 + 36 (angle A) = 90

also x= 51

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The school that Mary goes to is selling tickets to a spring musical. On the first day of ticket sales

andrezito [222]

Answer:

The cost of one adult ticket is $13, and the price of one student ticket is $4.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

x is the cost of an adult ticket

y is the cost of a student ticket.

6 adult tickets and 1 student ticket for a total of $82

This means that

$6x + y = 82$

$y = 82 - 6x$

The school took in $51 on the second day by selling 3 adult tickets and 3 student tickets.

This means that

$3x + 3y = 51$

Simplifying by 3

$x + y = 17$

Since $y = 82 - 6x$

$x + 82 - 6x = 17$

$-5x = -65$

$5x = 65$

$x = \frac{65}{5} = 13$

$y = 82 - 6x = 82 - 6*13 = 82-78 = 4$

The cost of one adult ticket is $13, and the price of one student ticket is $4.

4 0

3 years ago

Given: △ABC, AB=5 sqrt 2 m∠A=45°, m∠C=30° Find: BC and AC will give brainliest!!! By the way the answer is not 5 and 3.66

Makovka662 [10]

Answer:

Therefore,

$BC=a=10\ units\\\\AC=b=13.66\ units$

Step-by-step explanation:

Consider a Δ ABC with

m∠ A = 45°

m∠ C = 30°

AB = c = 5√2

To Find:

BC = a = ?

AC = c = ?

Solution:

Triangle sum property:

In a Triangle sum of the measures of all the angles of a triangle is 180°.

$\angle A+\angle B+\angle C=180\\\\45+30+\angle B=180\\\ttherefore m\angle B =180-75=105\°$

We know in a Triangle Sine Rule Says that,

In Δ ABC,

$\frac{a}{\sin A}= \frac{b}{\sin B}= \frac{c}{\sin C}$

substituting the given values we get

$\frac{a}{\sin 45}= \frac{b}{\sin 105}= \frac{5\sqrt{2} }{\sin 30}$

∴ $\frac{a}{\sin 45}= \frac{5\sqrt{2} }{\sin 30}\\\\a=\sin 45\times \frac{5\sqrt{2} }{\sin 30}\\\\a=\frac{1}{\sqrt{2} }\times \frac{5\sqrt{2} }{0.5} \\\\\\a=\frac{5}{0.5} =10\\\therefore BC = a = 10\ units$

Similarly for 'b',

$\frac{b}{\sin 105}= \frac{5\sqrt{2} }{\sin 30}\\\frac{b}{0.9659}= \frac{5\sqrt{2} }{0.5}\\\\b=0.9659\times \frac{5\sqrt{2} }{0.5}\\\\b=\frac{6.8301}{0.5} \\\\b=13.66\\\therefore AC = b =13.66\ units\\$