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3 years ago

Please help! i need to pass this class!!

Mathematics

2 answers:

svetoff [14.1K]3 years ago

6 0

Answer:

m∠B = 54°

Step-by-step explanation:

Note: Complementary angles add up to 90°

Thus, m∠A and m∠B must add up to 90.

We can then write this equation.

x - 15 + x + 3 = 90

Simplify.

2x - 12 = 80

Add 12 to both sides.

2x = 102

x = 51

m∠B is (x + 3) , so m∠B = 51+ 3 = 54°

Just in case, let's double check. Plug 39 for x into m∠A to get

m∠A = 51 - 15 = 36

Then, plug the angle measures in.

36 + 54 = 90

90 = 90

Thus, the answer is correct.

I hope this helps! Feel free to ask any questions! :)

torisob [31]3 years ago

3 0

Angle B = 54°

Step-by-step explanation:

complimentary means they add up to 90

54 + 36 (angle A) = 90

also x= 51

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X + (2x + 5) = 3(x – 4)+7

eduard

Answer:

Not true

Step-by-step explanation:

x + (2x + 5) = 3(x – 4)+7

Opening bracket on left and side and distributing 3 over (x-4) on right hand side

x+2x+5=3x-3 x 4 + 7

adding like terms

3x+5=3x-12+7

3x+5=3x-5

Hence

5 = -5

Which is not possible , Hence the equation given to us is false.

5 0

3 years ago

The sutton police department must write, on average, 6 tickets a day to keep department revenues at budgeted levels. suppose the

lakkis [162]

The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then
$P(k \, events) = e^{-\lambda } ( \frac{\lambda ^{k}}{k!} )$

For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is
$P(k \, tickets/day)=e^{-6.5} ( \frac{6.5 ^{k}}{k!} )$
The distribution is graphed as shown below.

Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.