Half the length of the palindrome can be any possible sequence of the 26 available letters. The other half is constrained to be the reverse of the same sequence. For odd length sequences, the middle letter can be any of the 26.

So, for k even, the number of palindromes is 26^(k/2). For k odd, the number is 26·26^((k-1)/2) = 26^)((k+1)/2).

5 0

3 years ago

Problem #15: A box contains 4 black balls, 7 red balls, and 3 green balls. Three balls are

Liula [17]

Answer:i don't know

Step-by-step explanation:

3 0

2 years ago

Please help (puppy eyes)

-Dominant- [34]

First we have to find the decimal equivalent by dividing.
5 / 8 = 0.625

It can't be an Integer because decimals can't be intergers, so that's ruled out

It can't be repeating as it does end, so that's also ruled out

Since the decimal does end it can't be non-terminating, non-repeating

So the answer is Terminating Decimal by process of elimination

7 0

3 years ago