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Salsk061 [2.6K]
3 years ago
8

PLEASE ANSWER PLZZZ HELP

Mathematics
1 answer:
stich3 [128]3 years ago
3 0
0.0307 or what are you giving us here?
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The value of h(t) when t=\frac{15}{32} is 10.02.

Solution:

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h(t)=-16t^2+15t+6.5

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$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5

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           $=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5

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          $=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

        $=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}

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$h\left(\frac{15}{32} \right)=10.02

Hence the value of h(t) when t=\frac{15}{32} is 10.02.

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