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harkovskaia [24]
3 years ago
10

On friday 1/6 of band pracitce was spent trying on uniforms. the band spent 1/6 of practice on marching, the remaining practice

time was spent playing music. what fraction of practice time was spent playing music?
Mathematics
1 answer:
Stella [2.4K]3 years ago
4 0
4/6 of the time was spent to play music because 1/6 + 1/6 = 2/6
6/6 - 2/6 = 4/6
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75% of 7th graders are returning to school. If there are 300 7th graders returning to school, how many total 7th graders are the
bagirrra123 [75]

Answer:

there are 350 in all of the 7th grade

4 0
3 years ago
The combined volume of all the tanks at an aquarium is 1.25 X 106 gallons. The aquarium plans to install a new dolphin tank with
DaniilM [7]

1. The combined volume of all the tanks at the aquarium is written in Scientific notation. Keeping this on mind, you can write it as following:

(1.25)(10^{6})=1,250,000gallons

2. Now, you must sum the combined volume of all the tanks and the volume of  the new tank to calculate the total volume of all of them:Vt=1,250,000gallons+250,000gallons\\Vt= 1,500,000gallons

3. Now, you can write the result in Scientific notation, as following:

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3 0
3 years ago
Which expression is equivalent to √4j^4/9k^8?
solmaris [256]
\frac{ 2j^{2} }{ 3^{4} }
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6 0
3 years ago
Read 2 more answers
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
3 years ago
There are 2 pounds of clay in the art supplies. If mrs.jennings divides the clay evenly into bags and places 1/8 pound into each
lys-0071 [83]
16 bags because 2 divided by 1/8 is 16
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3 years ago
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