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jeka94
3 years ago
7

Which fractions are equivalent to twenty-five over forty-five? A. five over nine, fifteen over twenty-eight B. thirty over forty

-eight,seventy-five over one hundred thirty-five C. five ninths,seventy-five over one hundred thirty-five D. thirty-five over fifty-four,forty over one hundred eight
Mathematics
1 answer:
Reptile [31]3 years ago
3 0

Answer:

The answer is A

Step-by-step explanation:

25/45

= (25÷5)/(45÷5)

= 5/9

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with midpoint

m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4

with 1\le i\le10.

Over each subinterval, we interpolate f(x)=\sqrt{1+x^8} with the quadratic polynomial,

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

Then

\displaystyle\int_0^5f(x)\,\mathrm dx\approx\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It turns out that the latter integral reduces significantly to

\displaystyle\int_0^5f(x)\,\mathrm dx\approx\frac56\left(f(0)+4f\left(\frac{0+5}2\right)+f(5)\right)=\frac56\left(1+\sqrt{390,626}+\dfrac{\sqrt{390,881}}4\right)

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Compare this to actual value of the integral, which is closer to 1967.

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