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3 years ago

Can you help me please

Mathematics

1 answer:

Sever21 [200]3 years ago

8 0

Answer:

30.5

Step-by-step explanation:

Angle B = Angle D (Alt. Exterior)

61 = 2x

61/2 = 30.5

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I NEED HELP ASAP CAUSE I'M STUCK

MaRussiya [10]

Answer:

5. $4b^8c^3$

6. $30t^6v^1^0$

Step-by-step explanation:

5. $(-4b^6)(-b^2c^3)\\4b^8c^3$

6. $(10t^4v^5)(3t^2v^5)\\30t^6v^1^0$

4 0

3 years ago

a car left town A at 10:00 am and travelled towards town B at the average speed of 70 km/h. At the same time a truck left town B

Softa [21]

The important formula to this problem is $distance=rate(time)$ or $d=rt$

Now, the speed of the car is 70 km/h, and the speed of the truck is 50 km/h. It will take the two vehicles the same amount of time to meet since they both left at the same time. So, since distance equals rate times time, and t = time:

the distance of the car = 70t
the distance of the truck = 50t

Because they both left in opposite directions, and the towns are 420 kilometers apart, the equation for this would be

$70t+50t=420$

We now solve the equation.

$70t+50t=420 \\ 120t=420 \\ \frac{120t}{120}= \frac{420}{120} \\ t=3 \frac{1}{2}$

It will take the vehicles 3 and a half hours to meet. Since we're looking for the time, 3 and a half hours from 10:00 AM is 1:30 PM.

So, the car and the truck will pass each other at 1:30 PM.

8 0

4 years ago

Linear equations with distributing drag and drop

nadya68 [22]

Answer:

A.)

distribute
add 7x to both sides
add 6 to both sides
divide both sides by 10

B.)

distribute
combine like terms
subtract 12x from both sides
add 6 to both sides
divide both sides by 10

7 0

3 years ago

Patrick paid $4.00 for 5 organic peaches. How much did he pay per peach

leonid [27]

Answer:

80 cents

Step-by-step explanation:

divide the price by 5

4/5=.8

6 0

3 years ago

Read 2 more answers

An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.

saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

a = 10
b = 16
c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need $b^2 < a^2+c^2$ to be true in order for an acute triangle to happen.

So,

$b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5$

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

$c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\$

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0

3 years ago