Answer:
Average atomic mass = 63.62 amu.
Explanation:
Abundance of Co⁶³ = 69.2%
Abundance of Co⁶⁵ = 30.8%
Atomic mass of Co⁶³ = 63 amu
Atomic mass of Co⁶⁵ = 65 amu
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (63×69.2)+(65×30.8) /100
Average atomic mass = 4359.6 + 2002 / 100
Average atomic mass = 6361.6 / 100
Average atomic mass = 63.62 amu.
Answer:
a type of cell division that results in two daughter cells each having the same number and kind of chromosomes as the parent nucleus, typical of ordinary tissue growth.
Explanation:
The formula equation for the reaction between sulfuric acid and dissolved sodium hydroxide will be the same even if all products and reactants are in the aqueous or in the <span>liquid phase. It is as follows:
</span><span>
H2SO4 + 2NaOH = Na2SO4 + 2H2O</span>
The process by which green plants and some other organisms use sunlight to synthesize nutrients from carbon dioxide and water. Photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a by-product.
Answer:
0.667 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 250 mL
Initial concentration (C₁) = 12 M
Final concentration (C₂) = 4.5 M
Final volume (V₂) =?
The final volume of the solution can be obtained by using the dilution formula as illustrated below:
C₁V₁ = C₂V₂
12 × 250 = 4.5 × V₂
3000 = 4.5 × V₂
Divide both side by 4.5
V₂ = 3000 / 4.5
V₂ = 667 mL
Finally, we shall convert 667 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
667 mL = 667 mL × 1 L / 1000 mL
667 mL = 0.667 L
Thus, the volume of the solution prepared is 0.667 L
