Question

How many Liters of a 4.5 M HCL solution can be prepared by using 250.0 mL of a 12.0 M HCl solution?

Answer 1

Answer:

0.667 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 250 mL

Initial concentration (C₁) = 12 M

Final concentration (C₂) = 4.5 M

Final volume (V₂) =?

The final volume of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

12 × 250 = 4.5 × V₂

3000 = 4.5 × V₂

Divide both side by 4.5

V₂ = 3000 / 4.5

V₂ = 667 mL

Finally, we shall convert 667 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

667 mL = 667 mL × 1 L / 1000 mL

667 mL = 0.667 L

Thus, the volume of the solution prepared is 0.667 L