Answer:
The solubility of X in water at 17°C is 0.110 g/mL.
Explanation:
The water of a rock pool lined with mineral crystals is a <em>saturated solution</em> of said mineral, this means the concentration of X in those 36 mL is the solubility of compound X in water at 17 °C.
- This means<u> it is possible to calculate said solubility</u>.
The dilution of the sample is not relevant, nor is that 500 mL volume. What's important is that 3.96 g of X form a saturated solution with 36.0 mL of water, so the solubility is:
- 3.96 g / 36.0 mL = 0.110 g/mL
Answer:
Species present in the solution after complete reaction: 
Explanation:
First balance the chemical equation,
calculation of mili moles of each:
mili mole of AgNO3= 15mili mole;
mili mole of K2CrO4=10 mili mole;
From balance equation,
2 mili mole of AgNO3 reacts with 1 mili mole of K2CrO4
hence 1 mili mole of AgNO3 reacts with 0.5 mili mole of K2CrO4
15 mili mole of AgNO3 reacts with 7.5 mili mole of K2CrO4
so only 7.5 milimole will be used in the reaction and 2.5 mili mole left in solution.
species present in the solution after complete reaction:
are soluble in water so it will dissociate in the solution
The minerals in hard water react with soap and affect its cleaning capacity. It's still possible to use hard water when washing by using more soap. The additional soap will no longer be affected by the minerals in the water, so they can clean just as effectively, but you'll be wasting more soap this way.
1 CH4 (g) + 2 O2 (g) -----> CO2 (g) + 2H2O(l) ΔH= - 890 kJ
1 mol 2 mol
1) If ΔH has minus, it means "release". We need only "release" choices.<span>
2) From reaction
1 mol </span>CH4 (g) "releases" ΔH= - 890 kJ - We do not have this choice.
2 mol O2 (g) "release" ΔH= - 890 kJ, so
1 mol O2 (g) "release" ΔH= - 445 kJ
Correct answer is B.
Answer:
Yes
Explanation:
There are in double dash :) ( = )
