Answer:
Coefficients
Explanation:
Chemical equations are first written as a skeleton equation, which includes how many atoms each element and compound has. Skeleton equations are not 'balanced' because the number of atoms of each element on the left side (reactants) is not equal to the right side (products).
To balance a chemical equation, you can write coefficients in front of single elements and compounds. The coefficient multiplies with each single element and with each element in the compound.
For example, in this skeleton equation:
H₂ + Cl₂ => HCl
Reactants: Products:
2 hydrogen 1 hydrogen
2 chlorine 1 chlorine
Write the coefficient 2 in the products.
H₂ + Cl₂ => 2HCl
Now both reactant and product sides have 2 chlorine and 2 hydrogen, so the equation is balanced.
Answer:
HF
Explanation:
Hf has hydrogen bonding which is the strongest intermolecular forces. The stronger the IM forces, the higher the boiling point.
Answer:
communicable and non-communicable?
Answer:
- <em>The relationship between the scale divisions marked on the graduated cylinders and the estimated uncertainty in the volume measurements is</em> that <u>the larger the divisions the larger the uncertainty, and the smaller the divisions the smaller the uncertaintity.</u>
Explanation:
In general, <em>graduated cylinders</em> are marked with divisions (lines) at equal spaces or intervals. There are divisions that show the measure with a number and a series of intermediate not numbered divisions in between two numbered lines.
The <em>uncertainty </em>of the instrument is determined as half the difference between two consecutive marks.
So, the larger the interval of two consecutive marks the larger the uncertainty.
The attached image, taken from brainly.com/question/13102373, shows you some marks in a graduated cylinder.
Answer:

Explanation:
Hello!
In this case, since the Dalton's law help us to realize that the total pressure of a gas mixture is computed by adding the partial pressure of each composing gas, for the mixture formed by carbon dioxide, oxygen sulfide (should be hydrogen sulfide instead) and air, we can write:

Thus, given the total pressure and the partial pressures of both carbon dioxide and hydrogen sulfide, the partial pressure of the remaining air would be:

Therefore, we plug in to obtain:

Best regards!