All the electrons orbit the nucleus in specific orbitals
So, for compound with composition <span>NH3O</span> the correct structure would be <span>H2N−OH</span><span>. The structure of second type is stable for compound </span><span>NOF3</span> and may be observed for amine oxides like (C2H5)3N→O<span> or pyridine-N-oxide.
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Answer: Heat energy is the transfer of<u> thermal energy.</u>
Explanation:
Answer:
The equilbrium constant is 179.6
Explanation:
To solve this question we can use the equation:
ΔG = -RTlnK
<em>Where ΔG is Gibbs free energy = 12.86kJ/mol</em>
<em>R is gas constant = 8.314x10⁻³kJ/molK</em>
<em>T is absolute temperature = 298K</em>
<em>And K is equilibrium constant.</em>
Replacing:
12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK
5.19 = lnK
e^5.19 = K
179.6 = K
<h3>The equilbrium constant is 179.6</h3>
Answer:
The electronegativity of fluorine compare to the electronegativity of oxygen and chlorine as below
Explanation:
Fluorine has the highest electronegativity than oxygen, and chlorine.
Explanation
Generally the electronegativity increase across the period ( from the left to the right) and decreases down the group.
Both oxygen and fluorine are in period 2 in periodic table. since fluorine is on fur right side as compared to oxygen , fluorine has higher electronegativity than oxygen.
On the other side Fluorine and chlorine are in the same group in periodic table. fluorine is at the top of the group while chlorine is at the bottom therefore fluorine has higher electronegativity than chlorine.
