In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
Answer:
The price of an adult ticket it $5
Step-by-step explanation:
To solve this, we would find the system of equations. We would set up two equations that will represent the situation.
Let c = price per children ticket
Let a = price per adult ticket
Santo:
5c + 1a = 16.25
Hulda:
4c + 3a = 24
5c + 1a = 16.25 -> a = 16.25 - 5c
4c + 3a = 24
4c + 3(16.25 - 5c) = 24
4c + 48.75 - 15c = 24
-11c + 48.75 = 24
-48.75 -48.75
-11c = -24.75
/-11 /-11
c = 2.25
5c + a = 16.25
5(2.25) + a = 16.25
11.25 + a = 16.25
-11.25 -11.25
a = 5
a = $5 , c = $2.25
Answer: 83%
Explanation: idk how to explain but there ya go
