Let us assume that the given cylinder is 2.6 cm wide and its height is 3.1 cm. And, when piston is pushed down then the steady force is equal to 15 N.

Now, radius of the cylinder will be as follows.

r = $\frac{diameter}{2}$

= $\frac{2.6 cm}{2}$

= 1.3 cm

or, = 0.013 m (as 1 m = 100 cm)

As, area of cylinder = $\pi \times r^{2}$

= $3.414 \times (0.013 m)^{2}$

= $5.77 \times 10^{-4} m^{2}$

Relation between pressure and force is as follows.

Pressure = $\frac{Force}{Area}$

= $\frac{15 N}{5.77 \times 10^{-4} m^{2}}$

= 25996 $N/m^{2}$

Since, 1 $N/m^{2}$ = 1 Pa (as 1 kPa = 1000 Pa)

Therefore, P = 25996 $N/m^{2}$

= 25.99 kPa

= 26 kPa (approx)

Thus, we can conclude that pressure of the gas inside the cylinder is 26 kPa.

7 0

3 years ago

The magnetic field in the region between the poles of an electromagnet is uniform at any time, (1 point) but is increasing at th

olga nikolaevna [1]

Answer:

The magnitude of induced emf in the conducting loop is 0.99 mV.

Explanation:

Rate of increase in magnetic field per unit time = 0.090 T/s

Area of the conducting loop = 110 cm^2 = 0.0110 m^2

Electromagnetic induction is the production of an emf or voltage in a coil of wire due to a changing magnetic field through the coil.

Induced e.m.f is given as:

EMF = (-N*change in magnetic field/time)*Area

EMF = rate of change of magnetic field per unit time * Area

EMF = 0.090 * 0.0110

EMF = 0.00099 V

EMF = 0.99 mV

5 0

3 years ago