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Yuliya22 [10]
3 years ago
8

A football player kicks the ball at a 45 degree angle. Without an effect from the wind, the ball would travel 60.0m horizontally

. A) what is the initial speed of the ball? B) when the ball is near its maximum height it experiences a brief gust of wind that reduces its horizontal velocity by 1.50 m/s. What distance does the ball travel horizontally from the initial kick point? (In m)
Physics
1 answer:
Ronch [10]3 years ago
5 0
B when the ball is at its maxium height 
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An airplane dropped a flare from a height of 2860 feet above a lake. How many seconds did it take for the flare to reach the wat
KATRIN_1 [288]

Answer: 13.2 seconds.

Explanation: using equation of motion; S= ut +1/2at² where u = initial velocity=0

S= distance travelled

a = acceleration due gravity

t= time.

1 foot = 0.305m so,

S= 2860 feet =872.3m

S= ut+1/2 at²

872.3 = 0×t + 1/2×10 × t²

872.3 =0 + 5t²

T²= 872.3/5

T²= 174.46

Take the square root of T we then have;

t = 13.2 seconds to one decimal place.

8 0
3 years ago
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If the mass of an object stays the same and you apply more force what will happen to the objects motion
vovikov84 [41]

it will move the object if you apply force, because of that it will stay the same with newton's law.

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3 years ago
Which kind of energy transformation occurs during skydiving? A) mechanical to gravitational B) gravitational to kinetic C) kinet
Aleks [24]

B) gravitational to kinetic

Explanation:

The skydiver, when he is located at a certain height h above the ground, possesses gravitational potential energy, equal to:

U=mgh

where m is the mass of the skydiver, g is the gravitational acceleration and h is the height above the ground. As he falls, its height h decreases, while his speed v increases, so part of the gravitational potential energy is converted into kinetic energy, which is given by

K=\frac{1}{2}mv^2

so, we see that as v increases, the kinetic energy increases. Therefore the correct answer is

B) gravitational to kinetic

7 0
3 years ago
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A bimetallic strip (brass/steel), which is straight at room temperature, will be immersed in boiling water and allowed to equili
lakkis [162]

The thermal expansion of the materials allows to find the deflection of the bimetallist strip is Δy = 3.48 cm

given paramers

    * Bimetallic brass / steel tape

    * Initial temperature, room temperature T = 20ºC

    * Final temperature, boiling water  = 100ºC

    * initial length L₀ = 222mm (1cm / 10mm) = 22.2cm

    * thickness of bimetallic tape e = 0.036 inch (2.54 cm/1 inch) = 0.0914 cm

to find

    * perpendicular deviation or deflection (Δy)

Thermal expansion is the phenomenon of change in the length of a body due to the change in temperature, due to the increase in the length of the atomic and molecular bonds, macroscopically it is described by

        ΔL = α L₀ ΔT

ΔL and ΔT are the variation of the length and temperature respectively, L₀ is the initial length and α the coefficient of expansion ends.

In this case we have a strip formed by two materials with different coefficient of thermal expansion,

Brass       α_{brass}   = 19 10⁻⁶ ºC⁻¹

Steel       α_{steel}    = 11 10⁻⁶ ºC⁻¹

In the attached we can see a diagram of the process, as the temperature increases, the material with greater thermal expansion lengthens more, so the system must curve towards the center of the material with less

thermal expansion. Let's find the length of the strip for each material

brass          L_{f brass} - L₀ = α_{brass} L₀ ΔT

Steel           L_{f steel} - L₀ = \alpha_{steel} L₀ ΔT

Note that the initial length is the same for the two materials and that the strip is in thermal equilibrium at room temperature.

If we assume that we have an arc of circumference, we can write the length of the arc

        θ = L / r

where θ is the angle in radines, L the length of the arc and r the radius of curvature, let's write this equation for each material

brass     L_{f \ brass} =θ r₁

steel      L_{f \ steel} = θ r₂

we substitute in our equations

           θ r₁ - L₀ = α_{brass} L₀ ΔT

           θ r₂ - L₀ = α_{steel} L₀ ΔT

let's subtract the two equations

           θ (r₁- r₂) = L₀ ΔT (α_{brass} - α_{steel})

the thickness of the strip is

           e = r₁ -r₂

           θ = Lo \ \Delta T \ \frac{\alpha_{brass} - \alpha_{steel}}{e}

we calculate

           θ = 22.2 \ (100-20) \ \frac{(19-11) \ 10^{-6}}{0.0914}

           θ = 0.155 rad

Let's use trigonometry to find the perpendicular deflection

          tan θ = Δy / L₀

          Δy = L₀ tan θ

          Δy = 22.2 tan 0.155

          Δy = 3.48 cm

Using the thematic expansion of the two materials we find the deflection of the bimetallist strip is 3.38 cm

Learn more about thermal expansion here: brainly.com/question/18717902

7 0
3 years ago
The charge density of a uniformly charged disk 0.420 m in diameter is 2.92 ✕ 10−2 C/m2. What is the magnitude of the electric fi
iragen [17]

Answer:

E = {(Charge Density/2e0)*(1 - [z/(sqrt(z^2 - R^2))]}

R is radius = Diameter/2 = 0.210m.

At z = 0.2m,

Put z = 0.2m, and charge density = 2.92 x 10^-2C/m2, and constant value e0 in the equation,

E can be calculated at distance 0.2m away from the centre of the disk.

Put z = 0.3m and all other values in the equation,

E can be calculated at distance 0.3m away from the centre of the disk

3 0
3 years ago
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