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dybincka [34]
3 years ago
11

Is The neck is an example of a simple machine in the human body?

Physics
2 answers:
expeople1 [14]3 years ago
7 0
Yes, it is an simple machine in the human body.
tatyana61 [14]3 years ago
3 0
No it's the quite opposite simple
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Which scenario represents the strongest force? (Assume particles in all scenarios are the same distance apart.) a) Protons and n
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Answer: Option A

Explanation:

The force of attraction existent between the proton and neutron in the nucleus of an atom is extremely large. When the nucleus splits there is a large release of heat and energy larger than the force present in any of the other options listed.

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What is the speed of a wave with 3Hz frequency and a wavelength of 9 m
SIZIF [17.4K]

Answer:

Given

Frequency (f) = 3Hz

Wavelength = 9 m

Speed = ?

Explanation:

we know

Speed = wavelength * frequency

= 9*3

= 27 m/ s

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The wavelength of a wave on a string is 1.2 meters. If the speed of the wave is 60 m/s, what is the wave frequency? 5 points 0.2
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A 56 kg sprinter, starting from rest, runs 49 m in 7.0 s at constant acceleration.what is the sprinter's power output at 2.0 s,
alexgriva [62]
The sprinter is in uniform accelerated motion, and its initial velocity is zero, so the relationship betwen space (S) and time (t) is
S= \frac{1}{2} a t^2
where a is the acceleration. Using the data of the problem, we can find a:
a= \frac{2S}{t^2} = \frac{2 \cdot 49 m}{(7.0 s)^2} =2.0 m/s^2
So now we can solve the 3 parts of the problem.

a) power output at t=2.0 s
The velocity at t=2.0 s is
v(t)=at=(2.0 m/s^2)(2.0 s)=4.0 m/s

the kinetic energy of the sprinter is
K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(4.0 m/s)^2=448 J

and so the power output is
P= \frac{E}{t} = \frac{448 J}{2.0 s} =224 W

b) power output at t=4.0s 
The velocity at t=4.0 s is
v(t)=at=(2.0 m/s^2)(4.0 s)=8.0 m/s

the kinetic energy of the sprinter is
K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(8.0 m/s)^2=1792 J

and so the power output is
P= \frac{E}{t} = \frac{1792 J}{4.0 s} =448 W

c) Power output at t=6.0 s
The velocity at t=2.0 s is
v(t)=at=(2.0 m/s^2)(6.0 s)=12.0 m/s

the kinetic energy of the sprinter is
K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(6.0 m/s)^2=4032 J

and so the power output is
P= \frac{E}{t} = \frac{4032 J}{6.0 s} =672 W
8 0
3 years ago
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