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rusak2 [61]
3 years ago
15

What is the pressure in a gas container that is connected to an open-end U-tube manometer if the pressure of the atmosphere is 7

22 torr and the level of mercury in the arm connected to the container is 8.60 cm higher than the level of mercury open to the atmosphere A) 656 mm Hg
B) 8.60 mm Hg
C) 751 mm Hg
D) 860 mm Hg
Chemistry
1 answer:
mojhsa [17]3 years ago
5 0

Answer:

636 mm Hg

Explanation:

The pressure in the gas container is equal to the atmospheric pressure minus the height of mercury:

Atmospheric pressure = 722 torr = 722 mm Hg

Height = 8.60 cm = 86 mm Hg

Pressure = 722 - 86 = 636 mm Hg

So none of the given options is correct, the correct answer is 636 mm Hg.

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What does the steepness of the line on the graph represent?
hoa [83]

Answer:

The steepness of a hill is called a slope. The same goes for the steepness of a line. The slope is defined as the ratio of the vertical change between two points, the rise, to the horizontal change between the same two points, the run.

5 0
3 years ago
Calculate the reaction quotient Qp for the following redox reaction: 14H+ + Cr2O72- + 6Cl- ----> 2Cr3+ + 3Cl2 + 7H2O The reac
stich3 [128]

Answer:

Value of Q_{p} for the given redox reaction is 1.0\times 10^{-8}

Explanation:

Redox reaction with states of species:

14H^{+}(aq.)+Cr_{2}O_{7}^{2-}(aq.)+6Cl^{-}(aq.)\rightarrow 2Cr^{3+}(aq.)+3Cl_{2}(g)+7H_{2}O(l)

Reaction quotient for this redox reaction:

Q_{p}=\frac{[Cr^{3+}]^{2}.P_{Cl_{2}}^{3}}{[H^{+}]^{14}.[Cr_{2}O_{7}^{2-}].[Cl^{-}]^{6}}

Species inside third braket represent concentration in molarity, P represent pressure in atm and concentration of H_{2}O is taken as 1 due to the fact that H_{2}O is a pure liquid.

pH=-log[H^{+}]

So, [H^{+}]=10^{-pH}

Plug in all the given values in the equation of Q_{p}:

Q_{p}=\frac{(0.10)^{2}\times (0.010)^{3}}{(10^{-0.0})^{14}\times (1.0)\times (1.0)^{6}}=1.0\times 10^{-8}

7 0
3 years ago
A woolly rhinocerous skeleton (Coelodonta antiquitatis) found in Poland contains 1.30% of the C-14 found in living animals. How
krok68 [10]

Answer:

The organism died 35900 years ago

Explanation:

  • Half life C-14 is 5730 years.
  • For decay of radioactive nuclides: \frac{N}{N_{0}}=(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}
  • \frac{N}{N_{0}} is the fraction of radioactive nuclide remain present after t time and t_{\frac{1}{2}} is the half-life of radioactive nuclide
  • Here \frac{N}{N_{0}} is 0.013 and t_{\frac{1}{2}} is 5730 yeras

Plug-in all the values in the above equation:

0.013=(\frac{1}{2})^{\frac{t}{5730years}}

So, t = 35900 years

Hence the organism died 35900 years ago

4 0
3 years ago
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6 0
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What percent of total energy consumption in the u.s in 2010 came from hydroelectric power? select the closest answer
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Answer:

12% but u can put 8%

Explanation:

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