You are looking for an element in the fourth period and a transition metal. As most have about 3 valence electrons. Gallium and Scandium work perfectly.
Answer:
Fluorine is a <em>non-metal, fills its shell by gaining one electron </em>and<em> becomes a negatively charged ion.</em>
Explanation:
Fluorine have seven electrons in its outermost shell. This means that fluorine is located in Group 17(<em>Halogens</em>) in the Periodic Table. Note that halogens are non-metal elements. So fluorine is a non-metal.
Fluorine fills its shell by gaining one electron because it only needs one electron to achieve stable octet electron arrangement. ( it's easier to gain one electron than to lose all seven electrons in the outermost shell)
As fluorine atom gain one electron to achieve stable octet electron arrangement, its number of electrons becomes greater than its number of protons. So it becomes a negatively charged ion.
Answer:
1. wa. Molecular form.
2. wa. Molecular form.
3. sa. Ionic form.
Explanation:
1. hydrocyanic acid
HCN is a weak acid. That means that in the following equilibrium, the molecular form (HCN(aq)) is favored, and that's how it should be written in solution.
HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)
2. hypochlorous acid
HClO is a weak acid. That means that in the following equilibrium, the molecular form (HClO(aq)) is favored, and that's how it should be written in solution.
HClO(aq) ⇄ H⁺(aq) + ClO⁻(aq)
3. hydrochloric acid
HCl is a strong acid. That means that it completely dissociates and it should be written in the ionic form (H⁺(aq) + Cl⁻(aq)) when it is in solution.
HCl(aq) → H⁺(aq) + Cl⁻(aq)
