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Vilka [71]
3 years ago
5

How many moles of oxygen gas react to yield 0.200 mole water? . . C5H12(g) + 8 O2(g) = 5 CO2(g) + 6H2O(g)

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
4 0
C5H12(g) + 8 O2(g) = 5 CO2(g) + 6H2O(g) 
molar ratio of H2O to O = 6:8 
<span>we have 0.200 moles of H2O so we need 0.200 * 8/6 moles of O2 = 0.267 moles of O2 

Therefore, there will be 0.267 moles of O2 gas required to yield 0.2 moles of H20.


I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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What volume of oxygen (in L) is produced
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Answer:

12.36 L.

Explanation:

We'll begin by calculating the number of mole in 147.1 g of lead(II) nitrate, Pb(NO₃)₂. This can be obtained as follow:

Molar mass of Pb(NO₃)₂ = 207.2 + 2[14.01 + (16×3)]

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Next, we shall determine the number of mole of oxygen gas, O₂, produce from the reaction. This can be obtained as follow:

2Pb(NO₃)₂ —> 2PbO + 4NO₂ + O₂

From the balanced equation above,

2 moles of Pb(NO₃)₂ decomposed to produce 1 mole of O₂.

Therefore, 1.104 moles of Pb(NO₃)₂ will decompose to produce = (1.104 × 1)/2 = 0.552 mole of O₂.

Finally, we shall determine the volume occupied by 0.552 mole of oxygen gas, O₂. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.552 mole of O₂ will occupy = 0.552 × 22.4 = 12.36 L at STP.

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