B
Orbitals fill in a way that all of them first gain one electron, and then they start receiving the second electron if any are left. Thus, the three will fill with one electron each first and then the fourth will go into the first.
Answer:
See below.
Step-by-step explanation:
Ethers react with HI at high temperature to produce an alky halide and an alcohol.
R-OR' + HI ⟶ R-I + H-OR'
<em>Benzylic ethers</em> react by an Sₙ1 mechanism by forming the stable benzyl cation.
- PhCH₂-OR + HI ⟶ PhCH₂-O⁺(H)R + I⁻ Protonation of the ether
- PhCH₂-O⁺(H)R ⟶ PhCH₂⁺ + HOR Sₙ1 ionization of oxonium ion
- PhCH₂⁺ + I⁻ ⟶ PhCH₂-I Nucleophilic attack by I⁻
If there is excess HI, the alcohol formed in Step 2 is also converted to an alkyl iodide:
ROH +HI ⟶ R-I + H-OH
Thus, benzyl ethyl ether reacts to form benzyl iodide (a) and ethanol (b).
The ethanol reacts with excess HI in an Sₙ2 reaction to form ethyl iodide (c).
Did you get the answer bc it would rly help me out thanks
The standard heat of formation is the heat released or absorbed when you obtain the CrO₃ compound. So, the reaction basically involves the individual elements of the compound. The complete balanced chemical reaction for the formation of CrO₃ is:
<em>2 Cr + 3 O₂ → 2 CrO₃</em>
Answer:
C.
Explanation:
The increase the [H+] (concentration of H+ ions)
However, they decrease the pH if acids are added to any solution. Since they have more [H+] ions, they increase their conc. in the solution