All categories

3 years ago

How many moles of oxygen gas react to yield 0.200 mole water? . . C5H12(g) + 8 O2(g) = 5 CO2(g) + 6H2O(g)

1 answer:

4 0

C5H12(g) + 8 O2(g) = 5 CO2(g) + 6H2O(g)
molar ratio of H2O to O = 6:8
<span>we have 0.200 moles of H2O so we need 0.200 * 8/6 moles of O2 = 0.267 moles of O2

Therefore, there will be 0.267 moles of O2 gas required to yield 0.2 moles of H20.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>

You might be interested in

In fall, leaves may change from green to yellow or red. Explain in your own words what is happening inside the leaf with regard

natima [27]

Answer:

The pigment that causes leaves to be green is chlorophyll. ... As chlorophyll goes away, other pigments start to show their colors. This is why leaves turn yellow or red in fall. In fall, plants break down and reabsorb chlorophyll, letting the colors of other pigments show through.

3 0

2 years ago

What is a promblem based on charles' law?

LUCKY_DIMON [66]

Answer:

You will never know the exact volume with charles law

Explanation:

Doubling the temperature of gas doubles its volume, so long as the pressure and quantity of the gas are unchanged.

5 0

3 years ago

Read 2 more answers

What volume of oxygen (in L) is produced

sveticcg [70]

Answer:

12.36 L.

Explanation:

We'll begin by calculating the number of mole in 147.1 g of lead(II) nitrate, Pb(NO₃)₂. This can be obtained as follow:

Molar mass of Pb(NO₃)₂ = 207.2 + 2[14.01 + (16×3)]

= 207.2 + 2[14.01 + 48]

= 207.2 + 2[62.01]

= 207.2 + 124.02

= 331.22 g/mol

Mass of Pb(NO₃)₂ = 147.1 g

Mole of Pb(NO₃)₂ =?

Mole = mass / Molar mass

Mole of Pb(NO₃)₂ = 147.1 / 331.22

Mole of Pb(NO₃)₂ = 1.104 moles.

Next, we shall determine the number of mole of oxygen gas, O₂, produce from the reaction. This can be obtained as follow:

2Pb(NO₃)₂ —> 2PbO + 4NO₂ + O₂

From the balanced equation above,

2 moles of Pb(NO₃)₂ decomposed to produce 1 mole of O₂.

Therefore, 1.104 moles of Pb(NO₃)₂ will decompose to produce = (1.104 × 1)/2 = 0.552 mole of O₂.

Finally, we shall determine the volume occupied by 0.552 mole of oxygen gas, O₂. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.552 mole of O₂ will occupy = 0.552 × 22.4 = 12.36 L at STP.

Thus, the volume of oxygen gas, O₂ produced is 12.36 L.

6 0

2 years ago

Five strategies needed by learners to acquire knowledge and skills to make informed decisions and take appropriate actions to en

otez555 [7]

The five strategies could include; 1) research the question of clean water availability on line and in books (2 strategies), 2) interview or ask those affected by lack of availability of clean water and find out how it affects them 3) consult with other groups ie political groups also concerned with this question and find out what they did to ensure availability to clean water and lastly to take actions to fight for the accessibility of clean water for certain groups of people like the First Nations people on reserves in Canada.

6 0

2 years ago

Consider the elements: Na, Mg, Al, Si, P.

Olegator [25]

Answer:

The elements mentioned in the series are Na, Mg, Al, Si, and P. It can be seen that all these elements are located in the same period. The atomic number of the mentioned elements are Na-11, Mg-12, Al-13, Si-14, and P-15.

a) There will be an increase in the ionization energy with the increase in the element's atomic number across a period. More energy is needed to withdraw an electron from a completely occupied shell in comparison to an incompletely occupied shell.

The atomic number of Na is 11. When one electron is withdrawn from Na, it gets converted into the inert gas configuration of Ne. Thus, it will require more energy to withdraw the second electron from Na. Hence, Na exhibits the lowest second ionization energy.

b) Across the period, with an increase in the element's atomic number, the atomic radii reduces from left to right. Thus, P exhibits the smallest atomic radius.

c) The metallic nature of the elements reduces from left to right across a period in the periodic table. Thus, P is the least metallic element.

d) Diamagnetic signifies towards the element that exhibits pair electrons in its sub-shells. The electronic configuration of Mg is,

1s2 2s2 2p6 3s2

In Mg, no unpaired electrons are present, while all the remaining elements mentioned exhibit unpaired electrons in their valence shell. Thus, Mg is the diamagnetic element.

8 0

3 years ago