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3 years ago

Increase 2.75 by 1/4

Mathematics

2 answers:

alexgriva [62]3 years ago

7 0

3.4375 is the answer

Ivanshal [37]3 years ago

7 0

Answer:

1/4 in decimal form is 0.25. You can convert any fraction into a decimal by just diving the numerator by the denominator.

Every time you see a fraction sign basically “—“ it jsut means divide by.

Now you can just divide. 1/4= 0.25

now we Increase which just means add

2.75+0.25 =3

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Write the equation of a line that is parallel to y=0.6x + 3 and that passes through the point (-3,-5)

Mkey [24]

Answer:

$\large\boxed{y=0.6x-3.2}$

Step-by-step explanation:

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

We have

$y=0.6x+3$

Parallel lines have the same slope. Therefore we have the equation:

$y=0.6x+b$

The line passes through the point (-3, -5). Put the coordinates of the point to the equation and solve it for b:

$-5=0.6(-3)+b$

$-5=-1.8+b$ <em>add 1.8 to both sides</em>

$-3.2=b$

Finally we have:

$y=0.6x-3.2$

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3 years ago

Given the function f(x) = 4(2)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.

Dmitry [639]

Answer:

Step-by-step explanation:

I'm sure you want your functions to appear as perfectly formed as possible so that others can help you. f(x) = 4(2)x should be written with the " ^ " sign to denote exponentation: f(x) = 4(2)^x

f(b) - f(a)

The formula for "average rate of change" is a.r.c. = --------------

b - a

change in function value

This is equivalent to ---------------------------------------

change in x value

For Section A: x changes from 1 to 2 and the function changes from 4(2)^1 to 4(2)^2: 8 to 16. Thus, "change in function value" is 8 for a 1-unit change in x from 1 to 2. Thus, in this Section, the a.r.c. is:

------ = 8 units (Section A)

Section B: x changes from 3 to 4, a net change of 1 unit: f(x) changes from

4(2)^3 to 4(2)^4, or 32 to 256, a net change of 224 units. Thus, the a.r.c. is

224 units

----------------- = 224 units (Section B)

1 unit

The a.r.c for Section B is 28 times greater than the a.r.c. for Section A.

This change in outcome is so great because the function f(x) is an exponential function; as x increases in unit steps, the function increases much faster (we say "exponentially").

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3 years ago

Can someone help with the incorrect problems?

uranmaximum [27]

Answer:

Step-by-step explanation:

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3 years ago

Which intervals show f(x) decreasing? Check all that apply.

wolverine [178]

The intervals which represents those in which case the function, f(x) is reducing are as follows; [–2.5, –2], [–2, –1.5], [1.5, 2], [2, 2.5].

<h3>Which intervals naming the answer choices show the function f(x) decreasing?</h3>

It follows from the complete task content that the x-intervals between which the function value of f(x) is reducing are to be identified from the graph as attached.

On this note, by observation on the graph, it follows that from between the interval; [–2.5, –2], the function f(x) is decreasing.

Also, between the interval; [–2, –1.5], the function f(x) is decreasing.

Also, between the interval; [1.5, 2], the function f(x) is decreasing.

Also, between the interval; [2, 2.5], the function f(x) is decreasing.

Remark: The answer choices are as follows; [–2.5, –2] [–2, –1.5] [–1, 1] [1.5, 2] [2, 2.5) [2.5, 3]