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3 years ago

What is the sum of 8 and a number?

Mathematics

2 answers:

Nastasia [14]3 years ago

6 0

Okay... so then it would be 8+n= the number

miskamm [114]3 years ago

5 0

" the sum " means add

the sum of 8 and a number...

8 + n <== ur expression

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Stephanie is baking cookies for a party. The recipe calls for 3 cups of flour,

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2 years ago

?<br> 0.07<br> What is 70 x 10^2

Fofino [41]

Answer:

7000

Step-by-step explanation:

I think this is the answer

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3 years ago

1/5+1/7+3/21 the answer is

inessss [21]

Answer:

Step-by-step explanation:

We need to get all the fractions with a common denominator before we can solve the problem.

The only fractions that have a common multiple are 1/7 and 3/21, so we'll add these first and then add 1/5.

1/7 = 3/21

Add

$\frac{3}{21} + \frac{3}{21} =\frac{6}{21}$

6/21 = 30/105

1/5 = 21/105

$\frac{30}{105} + \frac{21}{105} = \frac{51}{105}$

Simplify

$\frac{51}{105} / \frac{3}{3} =\frac{17}{35}$

<h3>ANSWER: 17/35</h3>

I'm always happy to help :)

4 0

2 years ago

PLEASE HELP 7TH GRADE 100 PTS!!!

MariettaO [177]

f(x) = 5x is linear. Just a straight line with a slope of +5. So if the intervals are both a difference of 1, then the average rate of change will be the same.

f(x2) - f(x1) over x2 - x1. That's the formula for average rate of change.

So for Section A:

f(x) = 5x, (0,1)

[f(1) - f(0)]/(1-0)

= [5(1) - 5(0)]/1

=(5)/1

Do the same for section B and you'll get 5 as well.

I hope this helps you because I have no clue if my answer is right

6 0

3 years ago

The age of the Hawaiian islands gets older as you move from east to west. If the half-life of K-40 is 1.3 billion years, approxi

Mumz [18]

Answer:

$t \approx 750550.12\,yr$

Step-by-step explanation:

The time constant of the isotope is:

$\tau = \frac{1.3\times 10^{9}\,yr}{\ln 2}$

$\tau \approx 1.876 \times 10^{9}\,yr$

The decay of the isotope is described by the following model:

$\frac{m}{m_{o}} = e^{-\frac{t}{\tau} }$

Now, the time is cleared in the equation:

$t = -\tau \cdot \ln \frac{m}{m_{o}}$

$t = - (1.876\times 10^{9}\,yr)\cdot \ln 0.9996$

$t \approx 750550.12\,yr$

5 0

3 years ago