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3 years ago

How much power is indicated by each example?

Mathematics

2 answers:

Vlada [557]3 years ago

7 0

Yes it is 25 the guy above is correct

puteri [66]3 years ago

4 0

I would say 25 because the power to thre o’clock while I was at the park

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10(2.1q -2) + (7.5q+18)

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Answer:

Simplify the expression.

28.5q−2

Step-by-step explanation:

i think this what you would like

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2 years ago

Solve for .....x <br><br><br> 2x+8=4

Naya [18.7K]

Answer:

2x=-4

x=-2

Step-by-step explanation:

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3 years ago

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Answer:

1. no

2. 36+196=232 c=441 Obtuse.

3. x is greater than 3, less than 21.

Step-by-step explanation:

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2 years ago

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ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

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3 years ago

Calculate the difference. 0.9 − 0.245 *

const2013 [10]

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2 years ago

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