Answer: C=t+50
Step-by-step explanation: This equation means that Clare's score equals Tyler's score plus 50.
Only one choice is correct here.
Answer:
C. 16√3π in.
Step-by-step explanation:
Circumference of a circle = 2πr where
r is the radius of the circle.
Given the area of one of the smaller circle to be 48π in², we can get the radius of one of the smaller circle.
If A = πr²
48π = πr²
r² = 48
r = √48 in
The radius of one of the smaller circle is √48.
To get the circumference of the larger circle, we need the radius of the larger circle. The radius R of the larger circle will be equivalent to the diameter (2r) of one of the smaller circle.
R = 2r
R = 2√48 inches
Since C = 2πR
C = 2π(2√48)
C = 4√48π in
C = 4(√16×3)π in
C = 4(4√3)π in
C = 16√3π in
Thw circumference of the larger circle is 16√3π in.
This problem can be represented in a formula with fractions. To make it more simple, we are converting 5m30s to just pure seconds, which = 154 copies in 330 seconds.
You set up the formula like this: 154/330 = x/60. (it is x/60 because you want to know the x amount of copies per 60 seconds)
Cross multiply, you get 330x = 9240. Divide both sides by 330, you get:
x = 28 copies.
The final answer is 28 copies per minute
Step-by-step explanation:
we have
length =8in
breadth =6in
since . The length and width of the actual flower bed will be 24 times larger than the length and width in the drawing.
new
length=8×24=192in
breadth =6×24=144in
(b) What is the perimeter of the actual flower bed ? Show your work.
<em>answer:the perimeter of the</em><em> </em><em>actual flower bed</em><em> =2(l+b)</em>
<em> =2(l+b)=2(192+144)=672</em><em>in</em>
(a) What is the perimeter of the drawing? Show your work
<em>answer</em><em> </em><em>:</em><em> </em><em>the perimeter of the </em><em>drawing</em>
<em>=</em><em>2</em><em>(</em><em>8</em><em>+</em><em>6</em><em>)</em><em>=</em><em>9</em><em>6</em><em>in</em>
<em>(c) What is the effect on the perimeter of the flower bed with the dimensions are multiplied by 24? Show your work</em>
<em>p</em><em>e</em><em>r</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>flower </em><em>bed</em><em> </em><em>/</em><em>p</em><em>e</em><em>r</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>d</em><em>r</em><em>a</em><em>w</em><em>i</em><em>n</em><em>g</em>
<em>=</em><em>9</em><em>6</em><em>/</em><em>6</em><em>7</em><em>2</em><em>=</em><em>1</em><em>/</em><em>7</em>
<h3>
<em>perimeter</em><em> </em><em>of</em><em> </em><em>drawing</em><em> </em><em>is</em><em> </em><em>increased</em><em> </em><em>by</em><em> </em><em>7</em><em>t</em><em>i</em><em>m</em><em>e</em><em>s</em><em> </em><em>of</em><em> </em><em>perimeter</em><em> </em><em>of</em><em> </em><em>flower</em><em> </em><em>bed</em></h3>
