Answer:
No.
Step-by-step explanation:
No. 5 - 4.2 = 0.8
Answer:
Given that JN was bisected, JL ≅ LN
Given that KM was bisected, KL ≅ ML
∠JLK ≅ ∠MLN because of vertical angles.
∠JLK is contained by JL and KL.
∠MLN is contained by ML and LN.
Therefore ΔJKL ≅ ΔNML by the SAS postulate.
Step-by-step explanation:
The SAS postulate states that when you know two triangles have an equal angle, and that angle is formed by two sides that are equal in both triangles, the two triangles are congruent.
When a line is bisected, it means it was cut in two equal parts.
Since two lines were bisected and each form a side in the triangles, two sides are congruent.
The contained angles, ∠JLK and ∠MLN, are equal because of vertical angles. Vertical angles occur when two straight lines intersect. Angles that are opposite to each other are equal in all cases.
First you have to put it into point-slope form before you can write it in slope-intercept form which is y-y1=m(x-x1)
Y-1=2(x-1)
Distribute the 2 to the x and -1
Y-1=2x-2
Move it all to one side
Y=2x-1
Interest = p times R times T
Answer:
(b) 
Step-by-step explanation:
When two p and q events are independent then, by definition:
P (p and q) = P (p) * P (q)
Then, if q and r are independent events then:
P(q and r) = P(q)*P(r) = 1/4*1/5
P(q and r) = 1/20
P(q and r) = 0.05
In the question that is shown in the attached image, we have two separate urns. The amount of white balls that we take in the first urn does not affect the amount of white balls we could get in the second urn. This means that both events are independent.
In the first ballot box there are 9 balls, 3 white and 6 yellow.
Then the probability of obtaining a white ball from the first ballot box is:

In the second ballot box there are 10 balls, 7 white and 3 yellow.
Then the probability of obtaining a white ball from the second ballot box is:

We want to know the probability of obtaining a white ball in both urns. This is: P(
and
)
As the events are independent:
P(
and
) = P (
) * P (
)
P(
and
) = 
P(
and
) = 
Finally the correct option is (b) 